<span>8 - 2b = -2/3(12b + 6)
8 - 2b = -8b -4
8 + 4 = -8b + 2b
12 = -6b
b = -12/6
b = -2
So, your final answer is b = -2</span>
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Example 1 – Solve: 3x3 = 12x
Step 1: Write the equation in the correct form. In this case, we need to set the equation equal to zero with the terms written in descending order.
 3x^3-12=0
Step 2: Use a factoring strategies to factor the problem.
 3x(x^2-4)=0
3x(x+2)(x-2)=0
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
 3x=0 or x+2=0 or x-2=0
Step 4: Solve each factor that was set equal to zero by getting the x on one side and the answer on the other side.
 x=0 or x=-2 or x=
I hope this helped you!
we know that
The scale factor is equal to
we have
substitute
therefore
<u>the answer is</u>
