2x^2+20x = -38
2x^2 + 20x + 38 = 0
Divide both sides by 2.
x^2 + 10x + 19 = 0
The quadratic formula works very well here.
Let a = 1, b = 10 and c = 19
x = [-b +- sqrt{b^2 - 4ac}]/(2a)
Plug those values into the formula to find two answers for x.
One is negative and the other positive.
Good luck.
Minus 6 both sides
7x²-x-6=0
hmm
using ac method we get
7x²-7x+6x-6=0
group
(7x²-7x)+(6x-6)=0
7x(x-1)+6(x-1)=0
undistribute
(7x+6)(x-1)=0
set to zero
7x+6=0
7x=-6
x=-6/7
x-1=0
x=1
x=-6/7 or 1
Answer:
B. It is between 4 and 5
Step-by-step explanation:
When you square 4 you get 16. Do the same to 5 and you get 25.
Answer:
-11/12
Step-by-step explanation: