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lawyer [7]
2 years ago
13

When a mixture containing cations of Analytical Groups I–III is treated with H2S in acidic solution, which cations are expected

to precipitate? Analytical Groups I and II Analytical Group I only Analytical Group III only Analytical Groups II and III Analytical Group II only
Chemistry
2 answers:
Fantom [35]2 years ago
8 0

Answer:

Analytical Groups I and II

Explanation:

Precipitation reactions happen when anions and cations in aqueous solution mix together to form an insoluble ionic solid which is now referred to as a precipitate.

Whether or not a type of reaction like that takes place can be determined by utilizing the solubility principles for common ionic solids.

Tema [17]2 years ago
8 0

Answer:

Option D is the answer :

Analytical Groups II and III

Explanation:

Group II (Cu2+, Bi3+, Cd2+, Hg2+, As3+, Sb3+, Sn4+) cations produce very insoluble sulfides

(Ksp values less than 10-30) so they can be precipitated by low amounts of sulfide ion; this can be

achieved by adding an acidic solution of H2S.

Group III (Al3+, Cr3+, Fe3+, Zn2+, Ni2+, Co2+, Mn2+) cations produce slightly soluble sulfides

(Ksp values more than 10-20) so they can be precipitated by relatively high amounts of sulfide ion;

this can be achieved by adding a basic solution of H2S

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Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride
GalinKa [24]

Answer:

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

Explanation:

Complete question

Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride. What is the net ionic equation

Equilibrium equation between the undissociated acid and the dissociated ions

HF(aq)⇌H+(aq)+F−(aq)

Sodium hydroxide will dissociate aqueous solution to produce sodium cations, Na+, and hydroxide anions, OH−

NaOH(aq)→Na+(aq)+OH−(aq)

Hydroxide anions and the hydrogen cations will neutralize each other to produce water.

H+(aq)+OH−(aq)→H2O(l)

On combining both the equation, we get –  

HF(aq)+Na+(aq)+OH−(aq)→Na+(aq)+F−(aq)+H2O(l)

The Final equation is  

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

5 0
3 years ago
An atom has a mass number of 24 and 13 neutrons. what is the atomic number of this atom?
Elodia [21]
do ityou times 24×13=312.
3 0
3 years ago
What's the easiest way to find balance in a chemical equation?
ivann1987 [24]
Well not calculus because that has nothing, well mostly nothing to do with balancing chemical equation, so B or C. Now for me personally B is way faster, though C is sometimes faster if you get lucky the way to solve it is B
6 0
2 years ago
An atom has a mass number of 25 and 13 neutrons. what is the atomic number of this atom? express your answer as an integer.
Snowcat [4.5K]
13 because an atom has the same number of protons as neutrons
5 0
2 years ago
A solution is prepared by dissolving 27.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the
bagirrra123 [75]
The answer is 6.88.
Solution:
We can calculate for the percent composition of CaCl2 by mass by dividing the mass of the CaCl2 solute by the mass of the solution and then multiply by 100. The total mass of the resulting solution is the sum of the mass of CaCl2 solute and the mass of water solvent. Therefore, the percent composition of CaCl2 by mass is 
     % by mass = (mass of the solute / mass of the solution)*100 
                        = mass of solute / (mass of the solute + mass of the solvent)*100
                        = (27.7 g CaCl2 / 27.7g + 375g) * 100 
                        = 6.88
5 0
3 years ago
Read 2 more answers
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