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lawyer [7]
2 years ago
13

When a mixture containing cations of Analytical Groups I–III is treated with H2S in acidic solution, which cations are expected

to precipitate? Analytical Groups I and II Analytical Group I only Analytical Group III only Analytical Groups II and III Analytical Group II only
Chemistry
2 answers:
Fantom [35]2 years ago
8 0

Answer:

Analytical Groups I and II

Explanation:

Precipitation reactions happen when anions and cations in aqueous solution mix together to form an insoluble ionic solid which is now referred to as a precipitate.

Whether or not a type of reaction like that takes place can be determined by utilizing the solubility principles for common ionic solids.

Tema [17]2 years ago
8 0

Answer:

Option D is the answer :

Analytical Groups II and III

Explanation:

Group II (Cu2+, Bi3+, Cd2+, Hg2+, As3+, Sb3+, Sn4+) cations produce very insoluble sulfides

(Ksp values less than 10-30) so they can be precipitated by low amounts of sulfide ion; this can be

achieved by adding an acidic solution of H2S.

Group III (Al3+, Cr3+, Fe3+, Zn2+, Ni2+, Co2+, Mn2+) cations produce slightly soluble sulfides

(Ksp values more than 10-20) so they can be precipitated by relatively high amounts of sulfide ion;

this can be achieved by adding a basic solution of H2S

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0.250 moles of NaCl is dissolved in 0.850 L of solution. What is the molar concentration?
Nuetrik [128]

Considering the definition of molarity, the molar concentration is 0.294 \frac{moles}{liter}.

Molarity reflects the concentration of a solution indicating the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{amount of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}.

In this case, you know:

  • amount of moles of solute= 0.250 moles
  • volume= 0.850 L

Replacing in the definition of molarity:

molarity=\frac{0.250 moles}{0.850 L}

Solving:

molarity= 0.294 \frac{moles}{liter}

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Learn more about molarity with this example: brainly.com/question/15406534?referrer=searchResults

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2 years ago
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3 years ago
50g nitrous oxide combines with 50g oxygen form dinitrogen tetroxide according to the balanced equation below.
photoshop1234 [79]

Limiting reactant : O₂

Mass of  N₂O₄ produced = 95.83 g

<h3>Further explanation</h3>

Given

50g nitrous oxide

50g oxygen

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Required

Limiting reactant

mass of N204 produced

Solution

mol N₂O :

\tt =\dfrac{50}{44}=1.136

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2N₂O+3O₂⇒ 2N₂O₄

ICE method

1.136    1.5625

1.0416  1.5625    1.0416

0.0944    0          1.0416

Limiting reactant : Oxygen-O₂

Mass N₂O₄(MW=92 g/mol) :

\tt =mol\times MW=1.0416\times 92=95.83~g

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