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sladkih [1.3K]
3 years ago
11

A teaspoon of the carbohydrate sucrose (common sugar0contains 16 Calories (16 KCal). What is the mass of the teaspoon of the suc

rose if the average number of Calories for the carbohydrates is 4.1 Calories/g?
Chemistry
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

3.902 grams is the mass of the teaspoon of the sucrose.

Explanation:

Calories in 1 teaspoon of carbohydrate sucrose = 16 calorie

The average number of calories for the carbohydrates is 4.1 Calories/g

Then number of grams in 1 calorie =\frac{1}{4.1} g

Mass of 16 calories:

16 caloire=16\times \frac{1}{4.1 }g=3.902 g

3.902 grams is the mass of the teaspoon of the sucrose.

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1. john needs to create a buffered solution at a ph of 3.5 for his biomedical laboratory
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Answer:

Use a ratio of 0.44 mol lactate to 1 mol of lactic acid  

Explanation:

John could prepare a lactate buffer.

He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

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When iron, Fe, react with chlorine, Cl, the product is iron(II) chloride, FeCl. If 56.8 g of
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Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. An excess of AgNO3 is present.
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Toichiometry time! Remember to look at the equation for your molar ratios in other problems.
31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag         6851.65⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻   →   ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻  = 107.9 g Ag       ∅        | 63.5 g Cu | 1 mol Cu | 1 mol Ag              63.5

There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.

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2 years ago
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