Answer:
Probability at least one car will get punctured: 0.39347
Step-by-step explanation:
B(10,000 , 0.00005)
P(X ≥ 1) = 1 - P(X = 0)
= 1 - (1 - 0.00005)^10,000
= 1 - (0.99995)^10,000
= 1 - 0.60652...
= 0.39347 (probability that at least one car will get punctured)
As you can tell P(X ≥ 1) as we have to solve for the probability that at least one car will get punctured. That is of course 1 - [ P(X = 0) ].
Answer:
a) number 2 and 3 appeared a minimum number of times
b) number 5 appeared a maximum number of times
c) number 1, 4 and 6 appear an equal number of times (4 times). Also number 2 and 3 appear an equal number of times (1 time)
d) Even numbers turned up 9 times. The even numbers in a dice are 2 4 and 6. Add up how many times they came up: 1+4+4=9
f) Odd numbers turned up 11 times. The odd numbers in a dice are 1, 3 and 5. Add up how many times they came up: 4+1+6=11
Answer:
acute
Step-by-step explanation:
Hey there!
If we use pemdas:
P - Parentheses
E - Exponents
M - Multiplicatiom
D - Division
A - Addition
S - Subtractiom
We know we have to evaluate the exponent first. Two to the rid power is equal to 8. Therefore, we have:
2 - 4/2 + 8
Next, we do the division. -4/2 = -2, so we have:
2-2 + 8 = 0 + 8 = 8
Hope this helps!
Answer:
7 + 8x
Step-by-step explanation:
-11 + 2 (4x -1) + 6
=> -11 + 8x -2 + 6
=> -13 + 8x + 6
=> -7 + 8x
So, the simplified expression is 7 + 8x.