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Eduardwww [97]
3 years ago
11

Irrational number between 3.077243 and 3.0721​

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

3.066543

Step-by-step explanation:

This number is between 3.077243 and 3.0721

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You do mot have to exsplain the answer i just wat the correct answer<br> no links please
Elenna [48]

Answer:

144

Step-by-step explanation:

5 0
3 years ago
For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
Rus_ich [418]

To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:

The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\

Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

Then we get factor of the denominator as \left(2x-3\right)\left(x+2\right)

Thus \frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}

Now \mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\

Signs of x^2+x+3>0

\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0

x\frac{3}{2} is the required solution of the given inequality.

5 0
4 years ago
Read 2 more answers
Find the diameter of a cone that has a volume of 83.74 cubic inches and a height of 5 inches
Vedmedyk [2.9K]

Answer:

V = πr²(h/3)

Step-by-step explanation:

83.74 = πr²(5/3)

R = 4.00 in

Diamater = 2r = 2 x 4.00 = 8 inches

4 0
4 years ago
Question 2 (10 points)
Anton [14]

Answer:

C. Right

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Sets C and D are subsets of the universal set U.
Natali5045456 [20]

The require set (CUD)' and C'nD is {q, r, x, y} and  Ø.

<h3>Set theory</h3>

Sets are elements arranged in a specific pattern or way. Given the expression below;

U= {f, k, q, r, s, x, y }

C={f, s,y}

D = {f,x)

CUD is the union of two sets and given as:

C U D = {f, s, y, k}

(CUD)' = {q, r, x, y}

For the set C'nD

C' = {k, q, r,x}

C' n D =  Ø.

Hence the require set (CUD)' and C'nD is {q, r, x, y} and  Ø.

Learn more on set theory here: brainly.com/question/13458417

#SPJ1

7 0
2 years ago
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