Equations with absolute value:

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).
How to solve:


Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}
2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6
3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}
4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}
5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Answer:
5x-4y+5=0.
Step-by-step explanation:
1) if the point A(-5;-5) and B(3;5), the formula is:

2) according to the formula above:

or 5x-4y+5=0.
Answer:
28 grams
Step-by-step explanation:
8 x 3 = 24
24 + 4 = 28
Answer:
C. The decimal terminates after 2 decimal places.
Step-by-step explanation:
If we move twice to the right, we will see that it will now see 1.14. I will send you a picture.
hope this helps.