Answer:
5.8
Step-by-step explanation:
Answer:
P(0,0) = 2/12 times 1/11 = 1/66
Step-by-step explanation:
For probability questions, think of each event happening separately, it makes the maths easier to understand. For example, in this question, do not think of the two boys taking a fruit at the same time - that makes the maths complicated
.
Let Daniel take a fruit first, then Sean can take a fruit. There are two parts to consider.
P
r
o
b
a
b
i
l
i
t
y
=
number of desirable outcomes
total number of possible outcomes
For Daniel: there are 12 different pieces of fruit in the bowl, he just takes one without choosing a specific fruit. (random)
The chance that Daniel takes an orange is
2
12
Of the 12 pieces of fruit. 2 are oranges.
Now Sean: the numbers of fruit in the bowl have changed. There are now only 11 pieces of fruit in the bowl, and only 1 is an orange.
The chance that Sean takes an orange is
1
11
Option C
<u>SOLUTION:</u>
We need to find the value of B - CF
First find the value CF:
![CF=\left[\begin{array}{ccc}12&0&1.5\\1&-6&7\\\end{array}\right] \left[\begin{array}{ccc}-2&0\\0&8\\2&1\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%261.5%5C%5C1%26-6%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}12(-2)+0 *0+1.5*2&12*0+0.8+1.5*1\\1*(-2)+(-6)*0+7.2&1*0+(-6)*8+7.1\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%28-2%29%2B0%20%2A0%2B1.5%2A2%2612%2A0%2B0.8%2B1.5%2A1%5C%5C1%2A%28-2%29%2B%28-6%29%2A0%2B7.2%261%2A0%2B%28-6%29%2A8%2B7.1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![CF=\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now find value of B - CF:
![B-CF=\left[\begin{array}{ccc}2&8\\6&3\\\end{array}\right] -\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%268%5C%5C6%263%5C%5C%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-21%261.5%5C%5C12%26-41%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![B-CF=\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=B-CF%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
∴ the value of B - CF is ![\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D23%266.5%5C%5C-6%2644%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<em>I hope this helps....</em>
Answer:
So, exist 18564 different possibilities.
Step-by-step explanation:
We know that the eighteen passengers get on an airport shuttle at the airport. The shuttle has a route that includes six hotels, and passengers get off the shuttle at their hotel.
We calcuate how many different possibilities exist that eighteen passengers can choose six hotels. We get:

So, exist 18564 different possibilities.