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Gwar [14]
2 years ago
14

Workers at Sunny Acres Orchard picked 544 apples. They picked 328 honey crisp apples and the rest were Granny Smith apples. The

workers put the Granny Smith apples into bags with 12 apples in each bag. How many bags were needed for the Granny Smith apples?
Mathematics
1 answer:
qwelly [4]2 years ago
7 0

The first thing to solve this is to subtract 328 out of 544, which is 216, meaning 216 Granny Smith apples. Next you divide that by 12 to see how many bags of 12 there would be to get you 18. :)
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2. A local baseball stadium has a total of 2,414 seats, with 221 seats reserved for season ticket holders.
kogti [31]
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y = 2414 - (x + 221)
y = 2414 - x - 221
y = 2193 - x <=====
5 0
2 years ago
A phone company charges for service according to the formula: C(n) = 17 +0.05n, where n is the number of minutes
Volgvan
The y intercept is 17. You can see it clearly in the equation.
6 0
2 years ago
Consider the following function.
Kryger [21]

Answer:

See below

Step-by-step explanation:

I assume the function is f(x)=1+\frac{5}{x}-\frac{4}{x^2}

A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, x=0 is the only vertical asymptote.

B) Set the first derivative equal to 0 and solve:

f(x)=1+\frac{5}{x}-\frac{4}{x^2}

f'(x)=-\frac{5}{x^2}+\frac{8}{x^3}

0=-\frac{5}{x^2}+\frac{8}{x^3}

0=-5x+8

5x=8

x=\frac{8}{5}

Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:

f'(2)=-\frac{5}{2^2}+\frac{8}{2^3}=-\frac{5}{4}+\frac{8}{8}=-\frac{5}{4}+1=-\frac{1}{4}

f'(1)=-\frac{5}{1^2}+\frac{8}{1^3}=-\frac{5}{1}+\frac{8}{1}=-5+8=3

Therefore, the function increases on the interval (0,\frac{8}{5}) and decreases on the interval (-\infty,0),(\frac{8}{5},\infty).

C) Since we determined that the slope is 0 when x=\frac{8}{5} from the first derivative, plugging it into the original function tells us where the extrema are. Therefore, f(\frac{8}{5})=1+\frac{5}{\frac{8}{5}}-\frac{4}{\frac{8}{5}^2 }=\frac{41}{16}, meaning there's an extreme at the point (\frac{8}{5},\frac{41}{16}), but is it a maximum or minimum? To answer that, we will plug in x=\frac{8}{5} into the second derivative which is f''(x)=\frac{10}{x^3}-\frac{24}{x^4}. If f''(x)>0, then it's a minimum. If f''(x), then it's a maximum. If f''(x)=0, the test fails. So, f''(\frac{8}{5})=\frac{10}{\frac{8}{5}^3}-\frac{24}{\frac{8}{5}^4}=-\frac{625}{512}, which means (\frac{8}{5},\frac{41}{16}) is a local maximum.

D) Now set the second derivative equal to 0 and solve:

f''(x)=\frac{10}{x^3}-\frac{24}{x^4}

0=\frac{10}{x^3}-\frac{24}{x^4}

0=10x-24

-10x=-24

x=\frac{24}{10}

x=\frac{12}{5}

We then test where f''(x) is negative or positive by plugging in test values. I will use -1 and 3 to test this:

f''(-1)=\frac{10}{(-1)^3}-\frac{24}{(-1)^4}=-34, so the function is concave down on the interval (-\infty,0)\cup(0,\frac{12}{5})

f''(3)=\frac{10}{3^3}-\frac{24}{3^4}=\frac{2}{27}>0, so the function is concave up on the interval (\frac{12}{5},\infty)

The inflection point is where concavity changes, which can be determined by plugging in x=\frac{12}{5} into the original function, which would be f(\frac{12}{5})=1+\frac{5}{\frac{12}{5}}+\frac{4}{\frac{12}{5}^2 }=\frac{43}{18}, or (\frac{12}{5},\frac{43}{18}).

E) See attached graph

5 0
2 years ago
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Reptile [31]
Answer: y-8=-1(x+3)

the formula for pain-slope form is:

y-y_{1}=m(x- x_{1})

(where y_{1} =a known y coordinate & x_{1} =a known x coordinate.

Now just plug in the data...

y-8=-1(x--3)
y-8=-1(x+3)
5 0
2 years ago
What is the value of x in the solution set of -5x-15&gt;10+20x
spayn [35]

Answer:

The answer is x < -1

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Hoped this helped!

brainly, please?

3 0
3 years ago
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