Given :
Mass of gold ( Au ) is 212 gram.
To Find :
Atoms of gold present in 212 gram of gold.
Solution :
Molecular mass of gold is 197 gram.
So, number of moles of gold in 212 gram is :
Now, we know 1 mole of any element contains atoms.
So, number of atoms present in 1.076 moles are :
Hence, this is the required solution.
Answer: 59 grams
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
Given: mass of hydrogen = 6.6 g
mass of oxygen = 52.4 g
Mass of products = Mass of hydrogen + mass of oxygen = 6.6 +52.4 = 59 g grams
Thus mass or reactant = mass of water
Mass of reactants = mass of products = 59 g
Thus the mass of water initially present was 59 g.
All of the above
_______________________________________________
Answer:
NiS insoluble
Mg₃(PO₄)₂ insoluble
Li₂CO₃ soluble
NH₄Cl soluble
C₁₂H₂₂O₁₁ molecules
Explanation:
<em>Predict whether the following compounds are soluble or insoluble in water.</em>
Based on the solubility rules we can say:
- NiS: Sulfides of transition metals are highly insoluble.
- Mg₃(PO₄)₂: All phosphates (except those with metals of Group 1) are insoluble so Mg₃(PO₄)₂ is insoluble.
- Li₂CO₃: all salts of metals of Group 1 are soluble so Li₂CO₃ is soluble.
- NH₄Cl: all salts of ammonium are soluble so NH₄Cl is soluble.
<em>Which of the following best describes the solute in an aqueous solution of sucrose or C₁₂H₂₂O₁₁(aq)?</em>
Sucrose is a molecular compound in which atoms are linked through covalent bonds. Thus, it does not ionize in water (is a non-electrolyte) and when it dissolves it exists as C₁₂H₂₂O₁₁ molecules.