The balanced equation is:
4 NO(g) + O₂(g) ⇒ 2 N₂O₃(g)
The expression of the rate in terms of change in concentrations are:
![v = \frac{-\Delta [NO]}{4\Delta t } = \frac{-\Delta [O_2]}{1\Delta t } = \frac{\Delta [N_2O_3]}{2\Delta t }](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B-%5CDelta%20%5BNO%5D%7D%7B4%5CDelta%20t%20%7D%20%3D%20%5Cfrac%7B-%5CDelta%20%5BO_2%5D%7D%7B1%5CDelta%20t%20%7D%20%3D%20%5Cfrac%7B%5CDelta%20%5BN_2O_3%5D%7D%7B2%5CDelta%20t%20%7D)
When N₂O₃ is forming at 0.221 M/s, NO is disappearing at 0.442 M/s.
<h3>What is the reaction rate?</h3>
The reaction rate is the speed at which a chemical reaction takes place, defined as proportional to the increase in the concentration of a product per unit time and to the decrease in the concentration of a reactant per unit time.
- Step 1: Write the balanced equation.
4 NO(g) + O₂(g) ⇒ 2 N₂O₃(g)
- Step 2: Express the rate in terms of the change in concentration with time for each substance.
We will need to consider the stoichiometric coefficient of each species.
![v = \frac{-\Delta [NO]}{4\Delta t } = \frac{-\Delta [O_2]}{1\Delta t } = \frac{\Delta [N_2O_3]}{2\Delta t }](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B-%5CDelta%20%5BNO%5D%7D%7B4%5CDelta%20t%20%7D%20%3D%20%5Cfrac%7B-%5CDelta%20%5BO_2%5D%7D%7B1%5CDelta%20t%20%7D%20%3D%20%5Cfrac%7B%5CDelta%20%5BN_2O_3%5D%7D%7B2%5CDelta%20t%20%7D)
- Step 3: Given the rate of formation of N₂O₃ is 0.221 M/s, calculate the rate of disappearance of NO.
The molar ratio of NO to N₂O₃ is 4:2.
![\frac{0.221molN_2O3}{L.s} \times \frac{4molNO}{2molN_2O_3} = \frac{0.442 molNO}{L.s}](https://tex.z-dn.net/?f=%5Cfrac%7B0.221molN_2O3%7D%7BL.s%7D%20%5Ctimes%20%5Cfrac%7B4molNO%7D%7B2molN_2O_3%7D%20%3D%20%5Cfrac%7B0.442%20molNO%7D%7BL.s%7D)
The balanced equation is:
4 NO(g) + O₂(g) ⇒ 2 N₂O₃(g)
The expression of the rate in terms of change in concentrations are:
![v = \frac{-\Delta [NO]}{4\Delta t } = \frac{-\Delta [O_2]}{1\Delta t } = \frac{\Delta [N_2O_3]}{2\Delta t }](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B-%5CDelta%20%5BNO%5D%7D%7B4%5CDelta%20t%20%7D%20%3D%20%5Cfrac%7B-%5CDelta%20%5BO_2%5D%7D%7B1%5CDelta%20t%20%7D%20%3D%20%5Cfrac%7B%5CDelta%20%5BN_2O_3%5D%7D%7B2%5CDelta%20t%20%7D)
When N₂O₃ is forming at 0.221 M/s, NO is disappearing at 0.442 M/s.
Learn more about reaction rate here: brainly.com/question/1898560