If 0.0106 g of a gas dissolves in 0.792 L of water at 0.321 atm, what quantity of this gas (in grams) will dissolve at 5.73 atm?
1 answer:
Answer:
0.189 g.
Explanation:
This problem is an application on <em>Henry's law. </em> Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.Solubility of the gas ∝ partial pressure If we have different solubility at different pressures, we can express Henry's law as: <em>S₁/P₁ = S₂/P₂, </em>
S₁ = 0.0106/0.792 = 0.0134 g/L and P₁ = 0.321 atm
S₂ = ??? g/L and P₂ = 5.73 atm
So, The solubility of the gas at 5.73 atm (S₂) = S₁.P₂/P₁ = (0.0134 g/L x 5.73 atm) / (0.321 atm) = 0.239 g/L.
<em>The quantity in (g) = S₂ x V = (0.239 g/L)(0.792 L) = 0.189 g. </em>
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