Answer:
b) in the fourth round, there was one team left in the tournament.
c) no because with only one team left, the tournament ends.
Answer:
3/6 or 1/2
Step-by-step explanation:
y2-y1 = 8-2 = 6
x2-x1 = 3-0 = 3
The point would be (3,6) or if simplified (1,2)
HOPEFULLY THIS HELPED :)
Answer:
the answer is c now mark me brainliest please.
Step-by-step explanation:
all sides are congruent and it is a parallelogram.
<span>For the answer to the question above,this is a simple question.
z = (3.25-3.5)/.25= -1
p= .8413
then multiply 100 to get the percentage.
The answer will be
84.13% or 84% rounded to the whole number.
I hope my answer helped you with your problem above. Have a nice day</span>
Answer:
Step-by-step explanation:
If you graph there would be two different regions. The first one would be
![y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%7Bx%7D%20%5C%2C%5C%2C%5C%2C%5C%2C%2C%200%5Cleq%20x%20%5Cleq%201%20%5C%5C)
And the second one would be
.
If you rotate the first region around the "y" axis you get that
![{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_1%20%3D%202%5Cpi%20%5Cint%5Climits_%7B0%7D%5E%7B1%7D%20x%5Csqrt%7Bx%7D%20dx%20%3D%20%5Cfrac%7B4%5Cpi%7D%7B5%7D%20%3D%202.51%20%7D)
And if you rotate the second region around the "y" axis you get that
![{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_2%20%3D%202%5Cpi%20%5Cint%5Climits_%7B1%7D%5E%7B2%7D%20x%282-x%29%20dx%20%3D%20%5Cfrac%7B4%5Cpi%7D%7B3%7D%20%3D%204.188%20%7D)
And the sum would be 2.51+4.188 = 6.698
If you revolve just the outer curve you get
If you rotate the first region around the x axis you get that
![{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_1%20%3D%5Cpi%20%5Cint%5Climits_%7B0%7D%5E%7B1%7D%20%28%20%5Csqrt%7Bx%7D%29%5E2%20dx%20%3D%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%3D%201.5708%20%7D)
And if you rotate the second region around the x axis you get that
![{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20A_2%20%3D%20%5Cpi%20%5Cint%5Climits_%7B1%7D%5E%7B2%7D%20%282-x%29%5E2%20dx%20%3D%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20%3D%201.0472%20%7D)
And the sum would be 1.5708+1.0472 = 2.618