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velikii [3]
3 years ago
9

A die is rolled 20 times and the number of twos that come up is tallied. Find the probability of getting the given result.

Mathematics
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

Probability (P) (k successes out of n trials) = nCk * p^k * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!)

for this problem n=20, p = 1/6(probability of rolling 1 two) is approximately 0.1667

P ( of getting more that 3 two's) = 1 -P(0 two's out of 20 trials) -P(1 two out of 20 trials) -P(2 two's out of 20 trials) -P(3 two's out of 20 trials)

P ( of getting more that 3 two's) = 1 -0.026 -0.104 -0.198 -0.238 = 0.434

My answer is A

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X=-b/2a is the formula for finding the axis of symmetry
So x= -30/2(5)
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Because the axis of symmetry is -3, we know where to place our line, and we also know that the parabola is open downwards, which means that the vertex will be maximum. To find the vertex, plug in your values with the axis of symmetry as a midway point. Plug that in for x and so you should have the following:
F(x)
Y(f(x) and y variables are interchangeable) =5(-3)^2-30(-3)+49

Solve for y(f(x))
5(-3)^2-30(-3)+49
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Add numbers
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So, your vertex would be
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3 years ago
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Answer:

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4 0
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Answer:

there are no options listed, but some statements that are true about this question are:

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2 years ago
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