Answer:
20 g of MgSO₄.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Mg + H₂SO₄ —> MgSO₄ + H₂
Next, we shall determine the mass of Mg that reacted and the mass of MgSO₄ produced from the balanced equation. This is illustrated below:
Molar mass of Mg = 24 g/mol
Mass of Mg from the balanced equation = 1 × 24 = 24 g
Molar mass of MgSO₄ = 24 + 32 + (16×4)
= 24 + 32 + 64
= 120 g/mol
Mass of MgSO₄ from the balanced equation = 1 × 120 = 120 g
SUMMARY:
From the balanced equation above,
24 g of Mg reacted to produce 120 g of MgSO₄.
Finally, we shall determine the mass of MgSO₄ produced by the reaction of 4 g of Mg. This can be obtained as follow:
From the balanced equation above,
24 g of Mg reacted to produce 120 g of MgSO₄.
Therefore, 4 g of Mg will react to produce = (4 × 120)/24 = 20 g of MgSO₄.
Thus, 20 g of MgSO₄ is obtained from the reaction.
