Answer:
Step-by-step explanation:
<u>The equation of the circle:</u>
The center is (h, k)
<u>Wen the center is the origin we have, h = 0, k = 0:</u>
The only equation in same format is the first one
The equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x
<h3>How to evaluate the expression?</h3>
The expression is given as:
(8x)^-2/3 * (27x)^-1/3
Evaluate the exponent 8^-2/3
(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * (27x)^-1/3
Evaluate the exponent (27x)^-1/3
(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * 1/3(x)^-1/3
Multiply 1/4 and 1/3
(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^-2/3 * (x)^-1/3
Evaluate the exponent
(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-2/3 -1/3)
This gives
(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-1)
So, we have
(8x)^-2/3 * (27x)^-1/3 = 1/12x
Hence, the equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x
Read more about equivalent expression at
brainly.com/question/2972832
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(p+1) (p-1). solved this on paper . hope it helps .
Answer:
1: 47
2: 19
3: 7
4: 11
5: 31
Step-by-step explanation:
input the number next to F where x is. example: f(-2)= 8(-2)^2-4(-2)+7 and then solve using PEMDAS giving f(-2)=47 and so on.
The true statements are
The mean is near the median.
The mean is the best measure of center.
The five-number summary is the best measure of variation
<h3>What is a histogram? </h3>
A histogram is used to represent data graphically. The histogram is made up of rectangles whose area is equal to the frequency of the data and whose width is equal to the class interval.
If the mean is greater than the median, the histogram would be skewed to the right. If the mean is less than the median, the histogram would be skewed to the left.
To learn more about histograms, please check: brainly.com/question/14473126
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