<span>Th find the average speed of a trip we need to dived the total distance by the total time.
Let's find the total distance d.
d = (300 mi/h)(2.00 h) + 750 miles
d = 600 miles + 750 miles
d = 1350 miles
The total distance is 1350 miles
Let's find the total time t.
t = 2.00 hours + (750 mi / 250 mi/h)
t = 2.00 hours + 3.00 hours
t = 5.00 hours
The total time of the trip is 5.00 hours.
We can find the average speed.
d / t = 1350 miles / 5.00 hours
d / t = 270 miles/ hour
The average speed of the trip is 270 mi/h
(Note that the direction does not matter when we find the average speed.)</span>
Answer:
The time is 1.8s
Explanation:
The ball droped, will freely fall under gravity.
Hence we use free fall formula to calculate the time by the ball to hit the ground
![h= \frac{1}{2}g{t}^{2}](https://tex.z-dn.net/?f=h%3D%20%5Cfrac%7B1%7D%7B2%7Dg%7Bt%7D%5E%7B2%7D%20)
Where h is the height from which the ball is droped, g is the acceleration due to gravity that acted on the ball, and t is the time taken by the ball to hit the ground.
From the question,
h=16m
Also, let take
![g = 9.8m{s}^{-2}](https://tex.z-dn.net/?f=g%20%3D%209.8m%7Bs%7D%5E%7B-2%7D%20)
By substitution we obtain,
![16= \frac{1}{2}\times 9.8{t}^{2}](https://tex.z-dn.net/?f=16%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.8%7Bt%7D%5E%7B2%7D%20)
![\implies32=9.8{t}^{2}](https://tex.z-dn.net/?f=%20%5Cimplies32%3D9.8%7Bt%7D%5E%7B2%7D%20)
Diving through by 9.8
![\frac{32}{9.8}= \frac{ 9.8{t}^{2} }{9.8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B32%7D%7B9.8%7D%3D%20%5Cfrac%7B%209.8%7Bt%7D%5E%7B2%7D%20%7D%7B9.8%7D%20)
![\implies{t}^{2} =3.265](https://tex.z-dn.net/?f=%20%5Cimplies%7Bt%7D%5E%7B2%7D%20%3D3.265)
square root both sides, we obtain
![\implies t= \sqrt{3.265}](https://tex.z-dn.net/?f=%20%5Cimplies%20t%3D%20%5Csqrt%7B3.265%7D%20)
![t=1.8s](https://tex.z-dn.net/?f=t%3D1.8s)
Answer:
1.0s
Explanation:
distance = 1/2 × acceleration × time2 + intial speed × time
Answer: The answer is density