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ankoles [38]
2 years ago
15

How man significant figures does the following value gave 43.023

Physics
1 answer:
Varvara68 [4.7K]2 years ago
7 0

Answer:

It has 5 I hope this helps you

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The movement of water between the atmosphere, land, oceans, and even living things makes up the water cycle. Precipitation is on
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I have no idea

Explanation:

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A resistor is made out of a long wire having a length L. Each end of the wire is attached to a termina of a battery providing a
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Answer:

B) 2I

Explanation:

The equation that relates voltage, current and resistance is V=RI.

The equation for the resistance of a material in terms of its resistivity, length and cross-sectional area is R=\frac{\rho L}{A}

In this case, the length is divided by 2 while keeping its resistivity (since it's the same material) and area, which means the resistance gets divided by 2. Then, looking at the equation I=V/R and keeping V constant, one deduces that since the resistance now is half than before then current now must be twice as before.

This is all intuitive in fact, cuting a homogeneous resistor in half and leaving the rest of the variables constant makes twice as easy for the electrons to cross the conductor, thus twice the current (one has to know that all the variables involved behave linearly, as the equations show).

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3 years ago
An object speed is 7.2 m/s and its momentum is 360 kg m/s what is mass of object
MAXImum [283]
Momentum = mass × velocity
360 = mass × 7.2
mass = 360/7.2 = 50 kg

Hope it helped!!
8 0
3 years ago
What is the difference in the speed of sound on a warm day versus on a cold day?
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The sun is bright and when its cold there is no sun
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Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the
Doss [256]

Answer:

v_{su} = 19.44 m/s

Explanation:

m_{su}=5.68x10^{29}kg\\m_{sa}=5.68x10^{26}kg

T=9.29x10^8\\r_{o}=1.43x10^{12}

If the sun considered as x=0 on the axis to put the center of the mass as a:

m_{su}*r_{o}=(m_{sa}+m_{su})*r_{1}

solve to r1

r_1=\frac{m_{sa}*r_{o}}{m_{sa}+m_{su}}=\frac{5.68x10^{26}*1.43x10^{12}}{5.68x10^{26}+5.68x10^{26}}

r_1=1.428x10^9m

Now convert to coordinates centered on the center of mass.  call the new coordinates x' and y' (we won't need y').  Now since in the sun centered coordinates the angular momentum was  

L = \frac{m_{sa}*2*pi*r_1^2}{T}

where T = orbital period

then L'(x',y') = L(x) by conservation of angular momentum.  So that means

L_{sun}=\frac{m_{sa}*2*\pi *( 2r_{o}*r_1 -r_1^2)}{T}

Since

L_{su}= m_{su}*v_{su}*r_1

then

v_{su}=\frac{m_{sa}*2*pi*(2r_{o}*r_{1}-r_{1}^2)}{T*m_{sa}*r_1}

v_{su} = 19.44 m/s

7 0
3 years ago
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