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Ksivusya [100]
3 years ago
8

Please find the area of this figure

Mathematics
1 answer:
salantis [7]3 years ago
7 0

Answer:

Area: 8

i hope this helped! :)

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Plsss help me with this question!!!
Molodets [167]
There are 27 men in the train car.
69-15=54
54 divided by 2 = 27
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3 years ago
"At most" and "No more than" are both clue words for...<br> a) <br> c)≤<br> d)≥
polet [3.4K]

Answer:

d) ≤

Step-by-step explanation:

3 0
3 years ago
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The ratio of the length to the width of a picture is 5:2. The picture is enlarged so that its length is 15 inches now. What is t
Maru [420]
The answer is B.
The ratio is multiplied by three so 5 times 3 is 15 and 2 times 3 is 6.
8 0
3 years ago
Can someone help answer this question Ive tried a lot and couldnt do it.
aleksklad [387]

Answer:

1222

Step-by-step explanation:

You have a triangular prism on top of a rectangular prism.  The surface area is the sum of the areas of the exposed faces.

Starting with the triangular prism, the surface area is the area of the two triangular bases plus the area of the two rectangular sides (the bottom rectangular face is ignored).

A = ½ (10) (12) + ½ (10) (12) + (13) (9) + (13) (9)

A = 60 + 60 + 117 + 117

A = 354

The surface area of the rectangular prism is the area of the two rectangular bases (front and back), plus the two walls (left and right), plus the bottom, plus the top (minus the intersection with the top prism).

A = (19) (11) + (19) (11) + (9) (11) + (9) (11) + (19) (9) + (19) (9) − (10) (9)

A = 209 + 209 + 99 + 99 + 171 + 171 − 90

A = 868

So the total surface area is:

354 + 868

1222

5 0
3 years ago
1 Subtracting Fractions
antoniya [11.8K]

Step-by-step explanation:

The question is not properly structured but we can as well find the sum of 5/7 and 10 as shown;

\frac{5}{7}+ \frac{10}{1} \\The \ LCM \ is \ 7\\\\= \frac{5(1)+10(7)}{7}\\\\=   \frac{5+70}{7}\\\\= \frac{75}{7}  \\\\= 10 \frac{5}{7}

Hence the expression written in equivalent form of common denominator is \frac{5 + 70}{7}

The sum is 10 \frac{5}{7}

8 0
3 years ago
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