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3 years ago

PLEASE ANSWER FAST...WILL MARK BRAINLIEST IF ANSWERED NOW. 20POINTS

Mathematics

2 answers:

Setler [38]3 years ago

6 0

(4)(y^2+4y-21)=0

BY MIDDLE TERM SPLITTING

(4){y^2+(7y-3y)-21}=0

(4)(y^2+7y-3y-21)=0

(4){(y^2+7y)-(3y+21)}=0

(4){y(y+7)-3(y+7)}=0

(4)(y-3)(y+7)=0

HOPE THIS WILL HELP U

Otrada [13]3 years ago

5 0

they all multiple by 4 like y 2/4+ 4y- 21

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I need help with this problem and would really appreiciate a short explanation too.<br> 15 PTS

inysia [295]

okay. the point has an x and y value. place them into the equation.

1=m(1)+b

m=slope, and theequation tells you that slope is 7.

1=7(1)+b

now you need to figure out what b is.

1=7(1)+b

1= 7 +b

-7 -7

---------------

-6=B

b is 6. now place it into the equation, replacing the x and y values back.

y=7x-6.

write 7 and 6 in the boxes (the negative for the six has already been provided)

8 0

3 years ago

15:45 in simplest form

mylen [45]

15:45 in simplest form is 1:3

the LCM of 15 and 45 is 15, and when you divide both by 15, you get 1:3

7 0

3 years ago

I am 21 years old my father is 3 times my age how old eill i be when my father is 40

DENIUS [597]

Answer:

Well the answer is 13.3 so 13 years old

Step-by-step explanation:

(F,Y) = (63,21)

Y3=F so F/3=y

F= 40

Y=?

40/3=Y

40/3=13.3

4 0

2 years ago

Read 2 more answers

At time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m. a. Find t

larisa [96]

Answer:

Step-by-step explanation:

Given that at time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m

i.e. $s(t) = -t^3+15t^2-72 t$

Velocity is nothing but s'(t) = derivative of s

and acceleration is s"(t) = derivative of v(t)

$v(t) = -3t^2+30t-72\\=-3(t^2-10t+24)\\= -3(t-6)(t-4)$

a) v(t) =0 when t = 4 or 6

b) $a(t) = -6t+30$

a(t) =0 when t =5

c) Distance travelled by the body from 0 to 5 would be

$s(5)-s(0)\\= -5^3+15(5^2)-72(5)\\= -125+375-360\\=-110$

i.e. 110 miles (distance cannot be negative)

3 0

3 years ago

Solve for y 2x+y-3z=5

Elza [17]

Answer:

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

<u>To solve:</u>

The value of y.

$\Longrightarrow: \sf{\sqrt{2x+y-3z}=5}$

<u>First, you have to subtract by 2x-3z from both sides.</u>

$\Longrightarrow: \sf{2x+y-3z-\left(2x-3z\right)=25-\left(2x-3z\right)}}$

<u>Solve.</u>

$\Longrightarrow: \boxed{\sf{y=25-2x+3z}}}$

<u>Therefore, the correct answer is "A. y=-2x+3z+25".</u>

I hope this helps, let me know if you have any questions.

4 0

2 years ago

Read 2 more answers