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Gennadij [26K]
3 years ago
11

What would be the theoretical yield in grams of carbon dioxide in the reaction shown below if 30 g of C6H12O6 were reacted with

an excess of oxygen? C6H12O6 + O2 -> CO2 + H2O
Chemistry
1 answer:
Vinvika [58]3 years ago
8 0

Answer: Thus 44 g of CO_2 will be produced  if 30 g of C_6H_{12}O_6 were reacted with an excess of oxygen

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} C_6H_{12}O_6 =\frac{30g}{180g/mol}=0.17moles

The balanced chemical equation is:  

C_6H_{12}O_6 +6O_2(g)\rightarrow 6CO_2+6H_2O(g)

As C_6H_{12}O_6 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

According to stoichiometry :

1 mole of C_6H_{12}O_6 produce =  6 moles of CO_2

Thus 0.17 moles of C_6H_{12}O_6 will produce=\frac{6}{1}\times 0.17=1.0mole  of CO_2

 Mass of CO_2=moles\times {\text {Molar mass}}=1.0moles\times 44g/mol=44g

Thus 44 g of CO_2 will be produced  if 30 g of C_6H_{12}O_6 were reacted with an excess of oxygen.

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Which of the following naming rules would apply to CaCO3? A. metal + polyatomic anion B. polyatomic cation + nonmetal anion(ide)
Sveta_85 [38]
The naming rules for CaCO3 would be A. Metal+ Polyatomic Anion.
7 0
3 years ago
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A tank of water was contaminated with a colored dye (D). To determine the concentration of D, an analyst took 5.0-mL solution fr
alekssr [168]

Answer:

0.005 M

Explanation:

Given data:

volume of sample solution ( volume of D ) = 5.0 mL

volume of added stock solution ( V1 ) = 5.0 mL

concentration of added stock solution ( N1 )  = 0.02 M

Total volume of concentration  ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)

concentration of Total volume of sample ( C2 ) = 0.01

N2 = ( N1V1 ) / V2

     = ( 0.02 * 5 ) / 10 = 0.01 m

absorbance of sample solution ( A1 ) = 0.10

absorbance of additional sample solution ( A2 ) = 0.20

attached below is the remaining part of the detailed solution

3 0
2 years ago
How many moles of HCl are present in 40.0 mL of a 0.035 M solution? 1. 0.0014 mol 2. 0.0060 mol 3. 0.25 mol?
Vinil7 [7]
40.0mL(1 L/1000 mL) = 0.040 L 

<span>then plug into the formula M = moles/liters </span>

<span>0.035 M = moles/ 0.040L </span>

<span>multipy both sides by 0.040L, and you get 0.0014 moles </span>

<span>so the answer is 1</span>
4 0
3 years ago
1.For the first ten reactions, write a balanced reaction for each tube in which a reaction occurred. If there was no reaction, w
slamgirl [31]

The equations of reaction occurring in the tubes are as follows:

  • 2 MnO₄⁻ + 6 Br⁻ + 8 H⁺ → 2 MnO₂ + 3 Br₂ + 4 H₂O
  • 2 MnO₄⁻ + 6 I⁻ + 8 H⁺ → 2 MnO₂ + 3 I₂ + 4 H₂O
  • No reaction
  • 2 Fe³⁺ + 2 I⁻ → 2 Fe²⁺ + I₂

<h3>What are the reactions occurring in the tubes?</h3>

The reactions occurring in the tubes are redox reactions.

Based on the table the equations of reaction are as follows:

  • 2 MnO₄⁻ + 6 Br⁻ + 8 H⁺ → 2 MnO₂ + 3 Br₂ + 4 H₂O
  • 2 MnO₄⁻ + 6 I⁻ + 8 H⁺ → 2 MnO₂ + 3 I₂ + 4 H₂O
  • No reaction
  • 2 Fe³⁺ + 2 I⁻ → 2 Fe²⁺ + I₂

In conclusion, redox reaction are reactions in which electrons are transferred.

Learn more about redox reactions at: brainly.com/question/26750732

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6 0
2 years ago
11) If you have a density of 100 kg/L,, tell me the following:
jenyasd209 [6]

The unit of mass is 'Kilogram' which is written as 'kg' and volume, v = 10 L.

<h3>Equation :</h3>

To calculate the volume

Use formula,

density = mass / volume

density = 100 kg/L

mass  = 1000 kg

volume = mass / density

v = 1000/100

v = 10 L

<h3>What is density mass?</h3>

A substance, material, or object's mass density is a measure of how much mass (or how many particles) it has in relation to the volume it occupies.

To know more about volume :

brainly.com/question/1578538

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I understand the question you are looking for :

If you have a density of 100 kg/L, and a mass of 1000 units, tell me the following: First what are the mass units? Secondly, what is the volume?

8 0
1 year ago
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