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Butoxors [25]
2 years ago
12

Help me pls I will mark you as brain

Chemistry
2 answers:
umka2103 [35]2 years ago
5 0

Answer:

I,II and III

Explanation:

Hope this helps :)

Alex787 [66]2 years ago
4 0

Answer:

l and III is the answer.

hope it hepls

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Determination of your estimate determines the BLANK<br> and BLANK<br> of a piece of equipment.
Zina [86]

Answer:

scalpel,mask

Explanation:

4 0
2 years ago
If the amount of Adams if each type on the left and right sides of a reaction difference what must be done to balance it
Ivanshal [37]

Hey there,

Your answer would be

Coefficients are placed in front of the reactants and/or products

Hope this helps,

<h2>- <em>Mr. Helpful</em></h2>

8 0
3 years ago
PLEASE HELP, I WILL GIVE BRAINLIEST AND THANKS
jasenka [17]

Answer:

23dm

Explanation:

so you have to do 10g +13dm so the you have to times it by 3 three times

3 0
3 years ago
How can I balance this equation? TELL ME HOW you did it and all the steps and you will be the brainliest.
lianna [129]

Answer:

3 CH3CH2OH + 4 H2CrO4 + 6 H2SO4 --> 3 CH3COOH + 2 Cr2(SO4)3 + 13 H2O

Explanation:

To balance, start of with the groups that are common on both sides of the reaction equation;

In this case, these are the SO4 groups treating them as single units;

There are 3 on the right side and 1 on the left side, so we put 3 in front of the H2SO4 to balance this first;

Next, deal with the Cr, there are 2 Cr on the right side and 1 on the other side, so we put a 2 in front of the H2CrO4 to balance that;

Thirdly, we notice the C are already balanced as there are 2 on each side so this is fine;

Lastly, we can deal with the O and H;

Bearing in mind the numbers that are in front of the molecules now from prior balancing, there are 9 O and 16 H on the left side and 3 O and 5 H on the right;

7 H2O on the right side would balance the O, but gives us 18 H, which is 2 too many H;

If we were to put 2 in front of the two organic molecules (the ones with C) on either side, we would balance the O by having 6 H2O, but this gives 2 fewer H than necessary;

In order for the H to balance, we need to have 13/2 (or 6.5) H2O, which means we need 3/2 (or 1.5) in front of each organic molecule;

Since, it is not sensible to have 13/2 water molecules or 3/2 organic molecules, we can just multiply everything by 2;

Thus we end up with:

3 CH3CH2OH + 4 H2CrO4 + 6 H2SO4 --> 3 CH3COOH + 2 Cr2(SO4)3 + 13 H2O

Rules of thumb:

- When there are common chemical groups (e.g. SO4) on both sides of a reaction equation, treat them as single units

- Start of with balancing these common groups

- Thereafter, balance the atoms that appear in only one reactant and one product

- Proceed to balance the atoms that appear in more than one reactant or product

- Typically, you should deal with the O and H last

4 0
3 years ago
Help!! 29 pointss
yaroslaw [1]
10 is mixture of elements and compounds
11 is compound
12-15 are mixture of compounds
3 0
3 years ago
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