Answer:
2 NaOH + H2SO4 2 H2O + Na2SO4
How many grams of sodium sulfate will be formed if you start with 200.0
grams of sodium hydroxide and you have an excess of sulfuric acid?
355.3 grams of Na2SO4
200.0 g NaOH 1 mol NaOH 1 mol Na2SO4 142.1 g Na2SO4
40.00 g NaOH 2 mol NaOH 1 mol Na2SO4
= 355.3 g
Explanation:
Here are a few examples :)
iodine (I2)
naphthalene
aresenic (As)
ferrocene
water (H2O)
carbon dioxide (CO2)
Hope this helps :)
The pH value of the solution is mathematically given as
pH=2.35
<h3>What
pH value of the
solution?</h3>
Question Parameters:
pH during the titration of 20.00 mL of 0.1000 M dimethylamine,
with 0.1000 M HCl(aq) after 21.23 mL of the acid
Generally, the equation for the Chemical Reaction is mathematically given as
(CH3)2NH(aq), +Hcl ---> <---- (CH3)2NH2Cl(aq)
Therefore

HCL=0.00444M
WHere
HClaq--->H+(aq)+Cl-(aq)
Hence
H+=0.00444M
pH= -log{H+}
pH=log(0.00444)
pH=2.35
For more information on Chemical Reaction
brainly.com/question/11231920
Answer:
See explanation below
Explanation:
I found a picture of this exercise, to show you how to do this problem.
The first picture is the compound, and the second is the mechanism of reaction to do this claisen rearrangement.
Hope this helps
Basically since potassium chloride is an ionic compound as it consists of a metal and a nonmetal, the potassium atom will donate one of its valence electrons to chlorine that will accept it and as a result produce oppositely charged ions, where the K + ion and the Cl - ion will attract forming an ionic bond. The compound that results is potassium chloride.