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3 years ago

Draw the structure of bromous acid, hbro2. optimize formal charges.

Chemistry

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

STRUCTURE OF BROMOUS ACID: H–O–Br=O

In this structure, all the elements have a formal charge of zero. The formal charge of each element is calculated below: 

H: 1 – 1/2(2) – 0 = 0
O: 6 – 1/2(4) – 4 = 0
Br: 7 – 1/2(6) – 4 = 0
O: 6 – 1/2(4) – 4 = 0

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3 years ago

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lbvjy [14]

Answer : The correct option is, (A) 51.1%

Explanation :

Mass percent : It is defined as the mass of the given component present in the total mass of the compound.

Formula used :

$\text{Mass} \%H_2O=\frac{\text{Mass of }H_2O}{\text{Mass of }MgSO_4.7H_2O}\times 100$

First we have to calculate the mass of $H_2O$ and $MgSO_4.7H_2O$ .

Mass of $H_2O$ = 18 g/mole

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Now put all the given values in the above formula, we get the mass percent of $H_2O$ in $MgSO_4.7H_2O$ .

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3 years ago