Ethylene Burns in the presence of O₂ to produce CO₂ and H₂O vapors;
C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O
According to equation,
22.4 L (1 mole) C₂H₄ reacts completely to produce = 44.8 L (2 moles) of H₂O
So,
1.65 L of C₂H₄ on complete reaction will produce = X L of H₂O
Solving for X,
X = (1.65 L × 44.8 L) ÷ 22.4 L
X = 3.3 L of H₂O
Answer:
C3H8 + 5O2 => 3CO2 + 4H2O
Explanation:
Hydrocarbon combustion is the reaction between a hydrocarbon and O2 producing CO2 and water.
C3H8 + O2 => CO2 + H2O
First we balance the C and H.
C3H8 + O2 => 3CO2 + 4H2O
Now we balance O for the answer!
C3H8 + 5O2 => 3CO2 + 4H2O
Answer:
The flame will burn out
Explanation:
The oxygen will be kept out of the jar, without oxygen the flame cannot last long. The flame will eventually burn out. Nitrogen gas has no role to play in the burning. Nitrogen slows down the burning rate.
