Answer:
16:1
Explanation:
Atoms of element X weigh 32 times more than atoms of element Y. We can write this in a symbolic way.
mX = 32 mY [1]
where,
- mX and mY are the masses of X and Y, respectively
A compound has the formula: XY₂, that is, in 1 molecule of XY₂ there is 1 atom of X and 2 atoms of Y. The ratio of the mass of X to the mass of Y in this compound equals:
mX/2 mY [2]
If we substitute [1] in [2], we get:
mX/2 mY = 32 mY/2 mY = 16 = 16:1
Answer:
The Kc of this reaction is 311.97
Explanation:
Step 1: Data given
Kp = 0.174
Temperature = 243 °C
Step 2: The balanced equation
N2(g) + 3H2(g) ⇌ 2NH3(g)
Step 3: Calculate Kc
Kp = Kc *(RT)^Δn
⇒ with Kp = 0.174
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 Latm/Kmol
⇒ with T = the temperature = 243 °C = 516 K
⇒ with Δn = number of moles products - moles reactants 2 – (1 + 3) = -2
0.174 = Kc (0.08206*516)^-2
Kc = 311.97
The Kc of this reaction is 311.97
That would be a description of a solid if that’s what your looking for. If not ask me in the comments:)
Answer:
1.08 M
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 45 mL
Initial concentration (C₁) = 6 M
Final volume (V₂) = 250 mL
Final concentration (C₂) =?
The final concentration of the solution can be obtained by using the dilution formula as illustrated below:
C₁V₁ = C₂V₂
6 × 45 = C₂ × 250
270 = C₂ × 250
Divide both side by 250
C₂ = 270 / 250
C₂ = 1.08 M
Therefore, the final concentration of the solution is 1.08 M.
