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3 years ago

15 POINTS NO CAP PLEASE HELP ME NEED RIGHT ANSWER

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

5 0

Answer:

y = -x + 3

Step-by-step explanation:

The line is going down so the slope will be NEGATIVE

The line starts at (0, 3) which means the y-intercept is 3

The slope is -1 or -x

dusya [7]3 years ago

3 0

Answer: c

Step-by-step explanation:

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Find the missing side of this right triangle. 19 X X = 16 ✓[?]

julia-pushkina [17]

Answer:

x = sqrt(105)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

16^2 + x^2 = 19^2

256 + x^2 = 361

x^2 = 361 -256

x^2 =105

Take the square root of each side

sqrt(x^2) = sqrt(105)

x = sqrt(105)

8 0

2 years ago

What is the domain and range?

Rasek [7]

Answer:

Domain:- All real numbers

Range:-[3,infinite)

Step-by-step explanation:

In the function there's no value of x for which it is not defined thus domain is R.

Now a modulus will have always it's minimum value 0 thus minimum value of function is 0+3=3. And Max value of a modulus is infinite so infinite+3=infinite.

6 0

3 years ago

Explain what a, h, and k do to transform the following equation. Be sure to mention the shift or transformation each variable do

dangina [55]

Answer:

a: vertical stretch

h: horizontal translation (remember not to get signs mixed up!)

k: vertical translation

3 0

3 years ago

Read 2 more answers

Given vectors A (2,-1,5), B (4,3,-2) & C (5,4,0), find:?

MrRissso [65]

A) 4a - 3b + 2c

4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =

= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)

Answer: (6, - 5, 26)

b) magnitude of vector b

$\sqrt{4^2+3^2+(-2)^2} = \sqrt{16+9+4} = \sqrt{29} ~ 5.4$

c) vector of length 7 parallel to vector c

=> m(5,4,0) = (5m,4m,0)

=> $\sqrt{(5m)^2+(4m)^2+0}= \sqrt{25m^2+16m^2}= \sqrt{41m^2}=m \sqrt{41}=7$

=> m = 7 / √41 ≈ 1.093

=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)

Answer: (5.465 , 4.372 , 0)

7 0

3 years ago

If sinA =3/5 and A+B =90 find cosB

-Dominant- [34]

$A+B=90^o\to B=90^o-A\\\\\cos B=\cos(90^o-A)=\cos90^o\cos A+\sin90^o\sin A\\\\=\cos A+1\cdot\dfrac{3}{5}=0+\dfrac{3}{5}=\dfrac{3}{5}\\\\\boxed{\cos B=\dfrac{3}{5}}$

$Used:\\\\\cos(x+y)=\cos x\cos y+\sin x\sin y\\\\\cos90^o=0,\ sin90^o=1$

Other method:

Look at the picture.

$\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{3}{5}\to opposite=3\ and\ hypotenuse=5$

$\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\adjacent=3\ and\ hypotenuse=5\to\cos B=\dfrac{3}{5}$

8 0

3 years ago