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Brums [2.3K]
3 years ago
8

15 POINTS NO CAP PLEASE HELP ME NEED RIGHT ANSWER

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
5 0

Answer:

y = -x + 3

Step-by-step explanation:

The line is going down so the slope will be NEGATIVE

The line starts at (0, 3) which means the y-intercept is 3

The slope is -1 or -x

dusya [7]3 years ago
3 0

Answer: c

Step-by-step explanation:

You might be interested in
X^2-5x=-4 . I need to find the zeroes
GrogVix [38]
The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:

X² - 5x + 4 = 0

Factor the equation:

(x - 1)(x - 4) = 0

Now calculate each piece separately, starting with the first one:

x - 1 = 0

Add 1 to both sides of the equation:

x = 1

We have proven that x = 1. Now calculate the second piece:

x - 4 = 0

Add 4 to both sides of the equation:

x = 4

We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.

I hope this helps!
4 0
4 years ago
Please help and dont worry this isnt a test
Inga [223]

B because when 9 is divided by 5 it cant be 1

8 0
3 years ago
What is the median of this set of data? 1,2,5,6,9
nexus9112 [7]

Answer: 5

Step-by-step explanation:

The median is the middle number in the set.

{1, 2, 5, 6, 9} - there are five numbers.

The middle number is the 3rd one.

{1, 2, 5, 6, 9}

The median is 5.

8 0
2 years ago
Find three consecutive integers whose sum is 35.
DIA [1.3K]

5, 10, and 20. (This is your answer.)

5 + 10 + 20 = 35.

These numbers are also consecutive, meaning each comes after the other on a number-line.

Hope this helps!

6 0
3 years ago
Find the area of the parallelogram that has adjacent sides Bold u equals Bold i minus 2 Bold j plus 2 Bold kand Bold v equals 3
Mice21 [21]

Answer:

The area of the parallelogram is A=\sqrt{26}.

Step-by-step explanation:

Let's rewrite these two vectors:

u=i-2j+2k

v=0i+3j-k    

Let's recall that the area of the parallelogram is the magnitude of the cross product between these vectors.            

We can use the Determinant method to find it.        

u \times v=\left[\begin{array}{ccc}i&j&k\\1&-2&2\\0&3&-1\end{array}\right] = i((-2)*(-1)-2*3)-j(1*(-1)-2*0)+k(1*3-(-2)*0)=i(2-6)-j(-1)+k(3)=-4i+j+3k

Now, the magnitude is the square root of each component squared. It will be:

|u \times v|=\sqrt{(-4)^{2}+(1)^{2}+(3)^{2}}=\sqrt{16+1+9}=\sqrt{26}

Therefore the A=\sqrt{26}.      

I hope it helps you!

8 0
3 years ago
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