if a university want to maintain a 14:1 ration between students and teachers, how many teachers would be needed to accommodate 8
2 answers:
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Answer:
<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>
(0.5603,0.6529)
Step-by-step explanation:
<em>Step(i)</em>:-
<em>Given sample size 'n' =300</em>
Given data random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.
<em>Given sample proportion </em>
<em> </em>
level of significance = 90% or 0.10
Z₀.₁₀ = 1.645
<em>90% confidence interval for the proportion is determined by</em>
(0.6066 - 0.0463 ,0.6066 + 0.0463)
(0.5603,0.6529)
<u>final answer</u>:-
<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>
(0.5603,0.6529)
The greatest number of sandwiches that Olivia can make is 12.
3 slices of cheese will be on each sandwich
<u>Solution:</u>
Given that, Olivia has 48 slices of ham and 36 slices of cheese to make sandwiches.
We have to find what is the greatest number of sandwiches that Olivia can make? And how many slices of cheese will be on each sandwich?
Let the number of sandwiches be "n"
Then, number of slices of ham per sandwich
And, number of slices of cheese per sandwich
As slices can’t be fractions, "n" should be a factor of 48 and 36. So now let us find H.C.F of 48 and 36 as we want greatest number of sandwiches that Olivia can make.
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48
The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, and 36
The common factors are those which appear on both factors of 48 and 36 are 1, 2, 4, 6, and 12.
Out of these common factors, 12 is the greatest
So, H.C.F of 48 and 36 is 12, which means n = 12
Then, number of cheese slices per sandwich
Hence, 12 sandwiches can be made with 3 slices of cheese per sandwich.