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Anton [14]
3 years ago
11

Pls answer pls pls hurry

Mathematics
1 answer:
dusya [7]3 years ago
5 0

Answer: This can not be answered unless you choose a bigger photo.

Step-by-step explanation:

Sorry

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1.) Write an equation of the line that passes through the point (3,-2) and is
GarryVolchara [31]

Answer:

y = 2x - 8

Step-by-step explanation:

8 0
3 years ago
If zb⊥ya , find m<br><br>A. 28<br><br>B.46<br><br>C.56<br><br>D.62<br><br>I'll give you brainliest
prohojiy [21]
<h3>Answer:</h3>

A. 28

<h3>Step-by-step explanation:</h3>

We assume m is the measure of the marked unknown angles: ∠BZY ≅ ∠BZA

(5x +3)° = (2x +18)°

Divide by ° and subtract 2x+3:

... 3x = 15

... x = 5

Then ∠BZA = (2·5 +18)° = m = 28°

5 0
3 years ago
Chris labels every lattice point in the coordinate plane with the square of the distance from the point to the origin (a lattice
stiv31 [10]

Answer:

4 times

Step-by-step explanation:

A lattice point may be defined as the point of intersection of two grid lines or more than two grid lines that is placed in a regularly spaced points arrays. This is called a lattice point.

In the context, Chris tries to label every lattice point in a coordinate plane with its square of distance from the point to its origin. The lattice points means that the numbers are both the integers. So for number 25, Chris has to label 4 times

i.e. (55),(-5,5),(5,-5),(-5,-5)

4 0
3 years ago
A car travels 45km in an hour. In each of the next two hours, it travels 78km. What is the average speed of the car.
romanna [79]

Answer:

The average speed of car is 67 kilometers per hour.

Step-by-step explanation:

Given that:

Distance travelled in one hour = 45 km

Distance travelled in next 2 hours = 78*2 = 156 km

Total distance = 45+156 = 201

Total time = 1+2 =  3 hours

Average speed of the car = \frac{Total\ distance}{Total\ time}

Average speed of the car = \frac{201}{3}

Average speed of the car = 67 km/hr

Hence,

The average speed of car is 67 kilometers per hour.

7 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
4 years ago
Read 2 more answers
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