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GarryVolchara [31]
3 years ago
9

Here are two ways of paying for delivery from an online supermarket.

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0

Answer:

Option B will be cheaper.

Step-by-step explanation:

Option A:

1.99*80=159.20

Option B:

5.99*24=143.76

*you get 24 becasue there are 24 months in 2 years.

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Yum-Yum-Yum restaurant has just increased the wages they pay their employees. to help offset this added expense, Yum-Yum-Yum mus
nignag [31]

Answer:

12% of 7.99

=0.96$

so...

The cost after Markup

=7.99$+0.96$

<h2>=8.95$</h2>
3 0
3 years ago
Describe the transformation from the red figure to the blue figure.
SSSSS [86.1K]

Step-by-step explanation:

The blue figure is translated 2 units down and 6 units across from the red figure.

6 0
3 years ago
75=n+12 what is the full problem and check your answers with simplifacation
Neko [114]

Answer:

63

Step-by-step explanation:

Next time subtract 75 and 12 .-.

8 0
3 years ago
WILL GIVE BRAINLIEST IF CORRECT PLEASE ANSWER!!!!!
murzikaleks [220]

The amount of wrapping paper he use is 62.4 square inches

<h3>How to calculate the surface area of a prism</h3>

The formula for calculating the total surface area is expressed as:

Area = 4(area of triangle)

Find the area of the triangle

A = 0.5(6)(5.2)

A =3(5.2)

A = 15.6 square inches

TSA = 4(15.6)
TSA = 62.4 square inches

Hence the amount of wrapping paper he uses is 62.4 square inches

Learn more on total surface area here: brainly.com/question/1297098

6 0
2 years ago
Complete the steps to simplify (y^4/3•y^2/3)^-1/2. Apply the product of powers property to the expression inside the parentheses
MrRissso [65]

Option A

\left(y^{\frac{4}{3}} \cdot y^{\frac{2}{3}}\right)^{\frac{-1}{2}} = \left(y^{2}\right)^{\frac{-1}{2}}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\left(y^{\frac{4}{3}} \cdot y^{\frac{2}{3}}\right)^{\frac{-1}{2}}

<em><u>Product of powers property:</u></em>

The product of powers property tells us that when you multiply powers with the same base you just have to add the exponents

Which is represented as,

a^m.a^n = a^{m+n}

<em><u>Therefore, the given expression becomes,</u></em>

\left(y^{\frac{4}{3}+\frac{2}{3}}\right)^{\frac{-1}{2}}

Now add the exponents, we get

\left(y^{\frac{4+2}{3}}\right)^{\frac{-1}{2}}

Simplify the above expression

\left(y^{\frac{6}{3}}\right)^{\frac{-1}{2}}

Simplify the exponent of y, we get

\left(y^{2}\right)^{\frac{-1}{2}}

Thus Option A is correct

6 0
3 years ago
Read 2 more answers
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