Let's solve your equation step-by-step.
4(2x+8)=10x+2−2x+30
Step 1: Simplify both sides of the equation.
4(2x+8)=10x+2−2x+30
(4)(2x)+(4)(8)=10x+2+−2x+30(Distribute)
8x+32=10x+2+−2x+30
8x+32=(10x+−2x)+(2+30)(Combine Like Terms)
8x+32=8x+32
8x+32=8x+32
Step 2: Subtract 8x from both sides.
8x+32−8x=8x+32−8x
32=32
Step 3: Subtract 32 from both sides.
32−32=32−32
0=0
Answer:
All real numbers are solutions.
Answer:
Step-by-step explanation:
Lines l and m are the parallel lines and 't' is a transversal line,
Therefore, ∠1 ≅ ∠5 [Corresponding angle postulate]
∠5 ≅ ∠7 [Vertical angles theorem]
∠1 ≅ ∠7 [Transitive property]
Therefore, ∠1 ≅ ∠7 [Alternate exterior angles theorem]
Answer:
0.03259..
Step-by-step explanation:
8s-8 is answer
Just distribute
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
