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charle [14.2K]
2 years ago
8

Help please i dont know the answer explain if you want

Mathematics
2 answers:
tatyana61 [14]2 years ago
8 0
6. 6. 6
18. 9. 18
30. 12. 30

12x-6 and 6(2x-1) are equal
dsp732 years ago
6 0

please mark me as brainlist..

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Since opening night, attendance at Play A has increased steadily, while attendance at Play B first rose and then fell. Equations
Y_Kistochka [10]

Answer:

On 5th day and 13th day Attendance was equal for both plays and it was

231 for each .

Step-by-step explanation:

In order to find same attendance ,we need  plug both equation equal

         -x^2+26x+126 = 8x+191

        -x^2+26x-8x+126-191 = 0

        -x^2 +18x-65 =0

      multiplying both sides by -1 ,we get

      x^2 -18x+ 65 =0

        (x-5) (x-13) =0

         x =5 and x =13

On 5th day and 13th  day attendance was same.

And attendance can be obtained by plugging x =5 in either of equation

 y = 8(5)+191

   = 40 +191

  = 231

 

8 0
3 years ago
Evaluate the limit as h goes to 0 of (3+h)^4 -81/h
Montano1993 [528]

Answer:6

Step-by-step explanation:Take the derivative of the numerator and denominator, then evaluate the limit.

8 0
3 years ago
Antonio ran 129 laps at the park. Alan ran 20% more than that. how many laps did Alan run
Colt1911 [192]

Answer:

154.8

Step-by-step explanation:

20% is equal to 20/100= 0.20. So, 0.20 multiplied by 129 will give you 20% of 129 which is 25.8. If Alan ran 20% more then you add 25.8 to 129 which gives you an answer of 154.8.

Equation: 20/100= 0.2

                0.2* 129= 25.8

                25.8+129= 154.8

Alan ran 154.8 laps.

3 0
3 years ago
For the given function f(x) = 2.6x + 4.3, x is the number of years since 2000 and y (or f(x)) is the percent of students taking
dsp73

Answer:

  in 2005, 17.3 percent of students are taking at least one online course

Step-by-step explanation:

f(5) = 2.6(5) +4.3 = 17.3

The definition of the function f(x) tells you that f(5) = 17.3 means 5 years after the year 2000, 17.3 percent of students are taking at least one online course.

7 0
3 years ago
Permutations of the word "Congratulations"​
Mice21 [21]

Answer:

There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is  14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is  14!/(23)=10,897,286,400

5 0
2 years ago
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