What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
Answer:
6³ = 216
9² = 81
3⁴ = 81
18² = 324
Step-by-step explanation:
6³ = 6 · 6 · 6 = 36 · 6 = 216
9² = 9 · 9 = 81
3⁴ = 3 · 3 · 3 · 3 = 9 · 3 · 3 = 27 · 3 = 81
18² = 18 · 18 = 324
You are going to get the rate of the detects.
6 detects ÷ 114 light bulbs = 1/19 detects per light bulb
If there are 720 light bulbs, then the number of detects will be
720 light bulbs * 1/19 detects per light bulb = 37. 89 ≈ 38 detects
The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.
Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.
Let's look at your option:
, so the cotangent is defined here
, so the cotangent is not defined here
, so the cotangent is defined here
, so the cotangent is defined here
Answer:
y = 7 
Step-by-step explanation:
Use the given ordered pairs to find a and b
Using (0, 7 ), then
7 = a 
( = 1 ), thus
a = 7
y = 7 
Using (5, 1701 )
1701 = 7 
( divide both sides by 7 )
243 = ( take the fifth root of both sides )
b = ![\sqrt[5]{243}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B243%7D)
= 3 , thus
y = 7
