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8090 [49]
3 years ago
12

For the following right triangle, find the side length x. X 12 35 help pls

Mathematics
1 answer:
zvonat [6]3 years ago
5 0

Answer:

the length of side X is 37

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Find the A) slope B) Point Slope equation and C) Slope Intercept form of the line through points (9,18),(-4,14)
Lana71 [14]

Answer:


Step-by-step explanation:

A) Use the slope formula to find the slope  m.


m=4/13


B)  Use the point-slope formula,  y−y1=m(x−x1)  to find the equation of the line.


y=4/13x+198/13


C) Write in slope-intercept form,  y=mx+b.


y=4/13x+198/13





4 0
3 years ago
What is the simplified form of the following expression? 13[62 ÷ (52 – 42) + 9]
tatuchka [14]

Answer:

197.6

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write expression

13[62 ÷ (52 - 42) + 9]

Step 2: Brackets - Parenthesis (Subtract)

13[62 ÷ 10 + 9]

Step 3: Brackets - Division

13[6.2 + 9]

Step 4: Brackets - Addition

13[15.2]

Step 5: Multiply

197.6

3 0
3 years ago
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Plz plz plz help I don’t get this
Bumek [7]
It looks like it counts up by 2 when adding. so add 4, then add 6, then add 8, then add 10, etc. to find the output you simply add 2 more than the last time you added, to find the input, you subtract 2 more than last time. hope this makes sense haha.
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Hey can you please help me posted picture of question
Ronch [10]
The formulas for conditional probability are:
P(A\cap B')=P(A)\cdot P(B'|A)
P(A\cap B')=P(B')\cdot P(A|B').
Since P(A\cap B')= \frac{1}{6} and p(B')= \frac{7}{18}, you have the equation \frac{1}{6} = \frac{7}{18} \cdot P(A|B').
Therefore, P(A|B')= \frac{1}{6} : \frac{7}{18} =\frac{1}{6} \cdot \frac{18}{7} = \frac{3}{7}.
Answer: The correct choice is D.


8 0
3 years ago
Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5.
Elena-2011 [213]

Answer:

B - A = -6

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

x + 3y = -5

Subtract x from both sides

x - x + 3y = -5 - x

3y = -5 - x

Divide both sides by 3

\frac{3y}{3} = -\frac{5}{3} - \frac{x}{3}

y = -\frac{5}{3} - \frac{x}{3}

The slope of the line is the coefficient of x

Slope = - \frac{1}{3}

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of - \frac{1}{3}

Having calculated the slope, next is to calculate the equation of the line using the following formula;

m = \frac{y - y_1}{x - x_1}

Where m is the slope; m = - \frac{1}{3}; (x_1, y_1) = (-7,2)

Substitute these values in the formula above; the formula becomes

-\frac{1}{3} = \frac{y - 2}{x - -7}

-\frac{1}{3} = \frac{y - 2}{x +7}

Cross Multiply

-1(x+7) = 3(y-2)

Open brackets

-x - 7 = 3y - 6

Add x to both sides

x - x - 7 = 3y - 6 + x

-7 = 3y - 6 +x

Add 6 to both sides

-7 + 6 = 3y -6 + 6 + x

-1 = 3y + x

Multipby both sides by -3

-3(-1) = -3(3y + x)

3 = -9y - 3x

-9y - 3x = 3

-3x - 9y = 3

Comparing the above to Ax + By = 3

Ax = -3x\\A = -3

By = -9y\\B = -9

B - A = -9 - (-3)

B - A = -9 + 3

B - A = -6

3 0
3 years ago
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