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3 years ago

Please help me I need this fast

Mathematics

2 answers:

nignag [31]3 years ago

8 0

Answer:

110°

Step-by-step explanation:

180° in a triangle

180 - 80 - 30 = 70

180° on a straight line

180 - 70 = 110

exterior angle 110°

Minchanka [31]3 years ago

4 0

100 degrees I think....

I’m writing this because it said it was too short

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Solve this equation.

Anika [276]

Answer:

Answer: b = 58/5 or 11 3/5 or 11.6 decimal

Step-by-step explanation:

Solve for b:

b - (3 + 2/5) = 8 + 1/5

Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:

b - (5×3)/5 + 2/5 = 8 + 1/5

5×3 = 15:

b - (15/5 + 2/5) = 8 + 1/5

15/5 + 2/5 = (15 + 2)/5:

b - (15 + 2)/5 = 8 + 1/5

15 + 2 = 17:

b - 17/5 = 8 + 1/5

Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:

(5 b)/5 - 17/5 = 8 + 1/5

(5 b)/5 - 17/5 = (5 b - 17)/5:

(5 b - 17)/5 = 8 + 1/5

Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:

(5 b - 17)/5 = (5×8)/5 + 1/5

5×8 = 40:

(5 b - 17)/5 = 40/5 + 1/5

40/5 + 1/5 = (40 + 1)/5:

(5 b - 17)/5 = (40 + 1)/5

40 + 1 = 41:

(5 b - 17)/5 = 41/5

Multiply both sides of (5 b - 17)/5 = 41/5 by 5:

(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 41

Add 17 to both sides:

5 b + (17 - 17) = 17 + 41

17 - 17 = 0:

5 b = 41 + 17

41 + 17 = 58:

5 b = 58

Divide both sides of 5 b = 58 by 5:

(5 b)/5 = 58/5

5/5 = 1:

Answer: b = 58/5 or 11 3/5 or 11.6 decimal

5 0

4 years ago

#18 There are 8 students

S_A_V [24]

There are 20 students in the class.

8 0

4 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

3 years ago

The purpose of a statistical quality control chart is to identify when assignable causes of variation have entered the productio

MAXImum [283]

Answer:

TRUE

Step-by-step explanation:

Control charts employ the use of graphical displays to observe and monitor a process which could be either a manufacturing, production or business process to ensure that it is in a sate of control using statistical analysis. This graphical display will enable the visualization of interference or variation dues to certain causes or factors which might creep in to effect an unwanted variation in the production or business process. Hence, with the control chart, these variations would be detected and corrected to ensure that the production proesss is free from unwanted interference as much as possible.

8 0

3 years ago

Solve each equation. Check your solution.

solniwko [45]

Converting all to improper fractions
31/10s = 31/5
5×31s=31×10
155s = 310
s=310/155= 2

20/9=-4/5m
5×20=-4×9m
100=-36m
m=100/-36 = 72 28/36 = 72 7/9

-14/5=-7/2n
-14×2=5×-7n
-28=-35n
n =-28/-35
n=28/35

8 0

4 years ago