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Zolol [24]
3 years ago
5

I need help with this prob

Mathematics
1 answer:
Lerok [7]3 years ago
4 0
3x +2=180//////////////////
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A liquid storage container is being filled at a constant
guajiro [1.7K]

Answer:

16/3

Step-by-step explanation:

6 0
4 years ago
Which integer has the least value (-17,-7,-12,2)
butalik [34]
-17 because if there is a negative sign in front the greater the number the less value in has due to the negative sign
5 0
2 years ago
Determine whether the given equation has one solution, no solution, or infinitely many solutions. 2/3 x = 9-2 (-1/3 x + 3)
AlladinOne [14]

Answer:

no solution

thats the answer :)

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6 0
2 years ago
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
3 years ago
How many grams of sugar must be added to 60 grams of a solution that is 32% sugar to obtain a solution that is 50% sugar?
liraira [26]
60/100=0.6
0.6x32=19.2
0.6x50=30
30-19.2=10.8

The answer is 10.8 grams of sugar must be added to obtain a solution that is 50% sugar
6 0
3 years ago
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