The answer is Cl (chlorine)
The minimum mass of NaHCO3 that must be added to the spill to neutralize the acid is 27.216 grams
<h3>calculation </h3>
write the balanced chemical equation
2NaHCO3 +H2SO4 → Na2SO4 +2H2O +2CO2
find the moles of H2SO4 = molarity x volume in liters
volume in liters = 27/1000=0.027 l
moles is therefore= 0.027 x6=0.162 moles
by use of mole ratio of NaHCO3: H2SO4 which is 2:1 the moles of NaHCO3=0.162 x2=0.324 moles
mass of NaHCO3= moles of NaHCO3 x molar mass of NaHCO3(84g/mol)
= 84g/mol x 0.324=27.216 grams
Answer:
<h2>mass = 1102.50 g</h2>
Explanation:
The density of a substance can be found by using the formula
Making mass the subject we have
<h3>mass = Density × volume</h3>
From the question
Density of silver = 10.50 g/cm³
Volume = 105 cm³
Substitute the values into the above formula and solve for the mass
That's
mass = 10.5 × 105
We have the final answer as
mass = 1102.50 g
Hope this helps you
Answer:
a ) 1876.14 grams CaBr2
b ) 19.78 grams N2
sorry..i only have time to do the first two :)
Explanation:
Answer:
0.05142 M
Explanation:
Let's consider the neutralization reaction between KHP and NaOH.
KHC₈H₄O₄ + NaOH → H₂O + NaKC₈H₄O₄
12.39 mL of 0.04150 M NaOH were required for the neutralization. The moles that reacted are:
12.39 × 10⁻³ L × 0.04150 mol/L = 5.142 × 10⁻⁴ mol
The molar ratio of KHP to NaOH is 1:1. The moles of KHP that reacted are 5.142 × 10⁻⁴ mol.
5.142 × 10⁻⁴ moles of KHP were in 10 mL of solution. The concentration of the KHP solution is:
5.142 × 10⁻⁴ mol / 10 × 10⁻³ L = 0.05142 M
