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dybincka [34]
2 years ago
11

What do elements in the first two columns of the periodic table have in common?

Chemistry
1 answer:
coldgirl [10]2 years ago
5 0

Answer: b.) they tend to lose electrons to gain stability

Explanation:

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You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,
bonufazy [111]

Answer:

\frac{[F^{-}]}{[HF]} is larger

Explanation:

pK_{a}=-logK_{a} , where K_{a} is the acid dissociation constant.

For a monoprotic acid e.g. HA, K_{a}=\frac{[H^{+}][A^{-}]}{[HA]} and \frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}

So, clearly, higher the K_{a} value , lower will the the pK_{a}

In this mixture, at equilibrium, [H^{+}] will be constant.

K_{a} of HF is grater than K_{a} of HCN

Hence, (\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})

So, \frac{[F^{-}]}{[HF]} is larger

5 0
3 years ago
A charged rubber rod can pick up a small neutrally charged piece of paper by what process
seropon [69]
Ion induced dipole process
8 0
3 years ago
Which is one characteristic of producers?
ludmilkaskok [199]

Answer: They use other organisms for energy

Explanation:

8 0
3 years ago
Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th
artcher [175]

Answer:

The <u>equilibrium constant</u> is:

              k_c=0.0030M^{-2}

Explanation:

The correct equation is:

  •   N₂(g)    +    3H₂(g)    ⇄    2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

         k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}

Substituting:

        k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}

         k_c=0.0030M^{-2}

6 0
3 years ago
How many grams of barium chloride (BaCl2) are there in 0.187 mol?<br> 0.187 mol
igor_vitrenko [27]

Answer:

38.9 grams of BaCl_2

Explanation:

0.187 mol BaCl2 x \frac{208 g}{1 mol}

0.187 m x 208 g/m

0.187 x 208 g

38.896 g --> 38.9 g BaCl2

8 0
3 years ago
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