Ask question

Ask question

All categories

katen-ka-za [31]

3 years ago

9

What is the name of B2(SeO4)3

2 answers:

Gala2k [10]3 years ago

6 0

Answer:

Boron Selenate

Explanation:

The compound contains B^3+ and the selenate anion SeO4^2-.

Selenate (Se(VI)) is quite weakly adsorbed by oxides and clays almost at neutral pH. Hence, oxidation of Se(IV) to Se(VI) enhances selenium mobility and persistence in natural water bodies. High concentrations of selenate can occur in agricultural drainage waters in arid areas. Selenate is further found in irrigation waters across the USA.

Many selenate compounds are known having various counter ions.

Gnoma [55]3 years ago

4 0

This compound is Boron selenate. Molar mass of B2(SeO4)3 is 450.4948 g/mol.

You might be interested in

Some chemical factories make hydrogen gas (H2) using a process called steam methane reforming. In this process, methane (CH4) co

erica [24]

Answer:

steam and methane

Explanation:

5 0

2 years ago

Br+ is isoelectronic with noble gas?

ArbitrLikvidat [17]

Answer:

yes. I think

Explanation:

im not really sure though

4 0

2 years ago

Which is a chemical property of iron

Whitepunk [10]

a chemical property of iron is the ability to change it, hammer it, roll it, shape it etc

5 0

2 years ago

Read 2 more answers

Which one of these are correct?

Sergio [31]

The correct answer is the one in the middle. Mixing food coloring and water

3 0

2 years ago

The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime

krok68 [10]

Answer: The rate constant for the reaction is $3.96\times 10^{-3}min^{-1}$

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = $2.83\times 10^{-3}$

a - x = amount left after decay process = $3.06\times 10^{-4}$

$559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}$

$k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}$

$k=3.96\times 10^{-3}min^{-1}$

The rate constant for the reaction is $3.96\times 10^{-3}min^{-1}$

6 0

3 years ago