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LuckyWell [14K]
4 years ago
5

A sample of gas occurs 9.0mL at a pressure of 500mmHg. A new volume of the same sample is at 750mmHg. Use two significant figure

s in answer on volume.
Chemistry
1 answer:
Anit [1.1K]4 years ago
5 0

Answer:

V₂ = 6.0 mL

Explanation:

Given data:

Initial volume = 9.0 mL

Initial pressure = 500 mmHg

Final volume = ?

Final pressure = 750 mmHg

Solution:

According to Boyle's Law

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 500 mmHg × 9.0 mL / 750 mmHg

V₂ = 4500 mmHg .mL / 750 mmHg

V₂ = 6.0 mL

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Answer:

B

Explanation:

The reaction will occur naturally

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How many decigrams are in 4.6 decagrams?
11111nata11111 [884]

Answer:

\large \boxed{\text{460 dg}}

Explanation:

1. Convert decagrams to grams

\text{Mass} =  \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}

2. Convert grams to decigrams

\\text{Mass} =  \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}

3 0
4 years ago
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Expliquen como prepararian una solucion homogenea y heterogenea
muminat

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5 0
3 years ago
Technetium-104 has a half-life of 18.0 minutes. How much of a 165 g sample is left after 90.0 minutes?
asambeis [7]

Answer:

After 90 minutes 5.15625 g amount left from total of 165 g.

Explanation:

Given data:

Technetium-104 half life = 18.0 min

Total amount of sample = 165 g

Amount left after 90.0 min = ?

Solution:

First of all we will calculate the number of half lives passes.

Number of half lives = T elapsed / Half life

Number of half lives = 90 min /18.0 min

Number of half lives =  5

Amount left:

At time 0 = 165 g

At first half life = 165 g/ 2= 82.5 g

At 2nd half life = 82.5 g/2  = 41.2 g

At 3rd half life = 41.2 g/ 2 = 20.625 g

At 4th half life =  20.625 g/ 2  = 10.3125 g

At 5th half life = 10.3125 g /2 = 5.15625 g

Thus, after 90 minutes 5.15625 g amount left from total of 165 g.

5 0
3 years ago
How many moles are in 2.31*10^21 atoms of lead
Anon25 [30]
Hey there!:

Molar mass Lead  ( Pb ) = 207.2 g/mol

Therefore:

1 mole Pb --------------------- 6.02*10²³ atoms
? moles Pb -------------------- 2.31*10²¹ atoms

moles Pb = ( 2.31*10²¹ ) * 1 / ( 6.02*10²³ ) = 

moles Pb = ( 2.31*10²¹ ) / ( 6.02*10²³ ) = 

=> 0.00383 moles of Pb

Hope this helps ! 
6 0
3 years ago
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