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3 years ago

Someone answer this please...

Chemistry

2 answers:

boyakko [2]3 years ago

7 0

Answer:

120 mol Mg

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

120 moles H₂

<u>Step 2: Identify Conversions</u>

RxN: 3 mol H₂ = 3 mol Mg

<u>Step 3: Stoichiometry</u>

<u /> $120 \ mol \ H_2(\frac{3 \ mol \ Mg}{3 \ mol \ H_2} )$ = 120 mol Mg

siniylev [52]3 years ago

4 0

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>

$\huge\boxed{\text{Magnesium = 120 moles}}$

<h2>_____________________________________</h2><h2>Stoichiometry:</h2>

The study of relationship between the amounts of reactants and the amount of products in a chemical reaction as given by the balanced chemical equation of the reaction is called the Stoichiometry.

There are three types of stochiometric relationships,

Mass-Mass Relationship
Mass-Volume Relationship
Volume-Volume Relationship

<h3><u>ASSUMPTIONS</u></h3>

To solve the stochiometric questions, we suppose,

No side reactions takes place.
Reactants are completely converted into products.

<h2>_____________________________________</h2><h3> $\Large\textbf{Methods to Solve}$ </h3>

There are two methods to solve the stoichiometric problems,

By mass/volume

By moles

I prefer the moles method because it is easier to solve and the question is already given in the moles

<h2>_____________________________________</h2><h2> $\Huge\textbf{Question:}$ </h2>

$\Large\textbf{Reaction}$

$3Mg \ +\ 2H_3PO_4\ {\Longrightarrow}\ Mg_3(PO_4)_2_{\downarrow} \ +\ 3H_2_{\uparrow}$

<u>GIVEN DATA</u>

Hydrogen gas = 120 moles

Moles of Magnesium = X = ?

<h3><u>SOLUTION</u></h3>

Since only the value of hydrogen is given and value of magnesium is asked so we will only focus on them only. Thus,

$3Mg\ {\Longrightarrow}\ 3H_2_{\uparrow}$

In the balanced reaction, there are 3 moles of magnesium used and 3 moles of Hydrogen gas are produced, thus The ratio of magnesium and hydrogen is <u>1 : 1</u>. This means that Whatever amount of magnesium used, the same amount of hydrogen gas will be produced as the magnesium. This was the quick way to guess the answer but if you want to actually solve it here is how,

3 moles of magneisum produce 3 moles of Hydrogen gas

X moles of magnesium produce 120 moles of hydrogen gas

<u>FOR X MOLES</u>:

X = $\frac{120\ x\ 3}{3}$

Simplify the equation,

X = 120 moles

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

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3 years ago

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3 years ago

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Troyanec [42]

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2 years ago

A sample of benzene was vaporized at 25◦C. When 37.5 kJ of heat was supplied, 95.0 g of the liquid benzene vaporized. What is th

grandymaker [24]

Answer:

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Explanation:

Given data:

Mass of benzene = 95.0 g

Heat evolved = 37.5 KJ

Enthalpy of vaporization = ?

Solution:

Molar mass of benzene = 78 g/mol

Number of moles = mass/ molar mass

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3 years ago

(The radioisotope 224Ra decays by alpha emission via two paths to the ground state of its daughter 94% probability of alpha deca

pav-90 [236]

Answer:

a) ²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b) the Q-value of this reaction is 5.789 MeV

c) the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

Explanation:

The decay equation for the alpha decay is expressed as;

²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

Calculate the Q-value (in MeV) of this reaction.

Q = Mparent - Mdaughter -Mg

Q = MRa - MRn -Mg

= 224.020202 - 220.011384 - 4.00260305

= 0.00621495 amu

= 5.789 MeV

therefore the Q-value of this reaction is 5.789 MeV

Energy of alpha particle is expressed as;

E∝ = MQ / ( m + M)

now this is the maximum energy available for the daughter, ²²⁰Rn going to the ground state;

The energy of the alpha particle gives;

E∝ = 220(5.789) / ( 4 + 220) = 5.69 MeV

as given in the question,The other less frequent alpha occurring 5.5% of the time leaves the daughter nucleus in an excited state of 0.241 MeV above the ground state.

Therefore the energy of this alpha is

E∝ = 5.69 - 0.241 = 5.449 Mev

Therefore the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

Sketch of the nuclear decay scheme have been uploaded along side this answer.

7 0

3 years ago