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vazorg [7]
2 years ago
15

1. Calculate the volume of a 0.500mol sample of gas atSTP.​

Chemistry
1 answer:
gregori [183]2 years ago
4 0

Answer:

11.2 litres

Explanation:

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12. What is the mass, if the density is 2 and the volume is 6? *<br> 3<br> O 12<br> O 15
AURORKA [14]
The answer to this problem is =12
3 0
3 years ago
Many classic experiments have given us indirect evidence of the nature of the atom. Which of the experiments listed below did no
uranmaximum [27]

Answer:

Option A, The Rutherford experiment proved the Thomson "plum-pudding" model of the atom to be essentially correct.

Explanation:

Thomson's plum pudding model:

Plum pudding model was proposed by J.J Thomson. In Thomson's model, atoms are proposed as sea of positively charge in which electrons are distributed through out.

Result of Rutherford experiment:

As per Rutherford's experiment:

Most of the space inside the atom is empty.

Positively charge of the atom are concentrated in the centre of the atom known as nucleus.

Electrons are present outside the nucleus and revolve around it.

As it is clear that, result of Rutherford experiment did not supported the Thomson model.

4 0
3 years ago
The United States was the first modern
kicyunya [14]

Answer:

first modern?

Explanation:

4 0
3 years ago
Which of these time measurements is the smallest?
Anuta_ua [19.1K]

Answer:

In order to answer the question, we convert the measurements given to a common base unit. For this case, we use seconds.

A)   0.02 seconds

B)   0.02 teraseconds x (10^12 s / 1 terasecond) = 2x10^10 seconds

C)   2,500 milliseconds x (1 s / 1000 ms) = 2.5 seconds

D)   25,000 nanoseconds x (1 x 10^-9 s / 1 nanosecond) = 2.5 x 10^-5 seconds

So ,The correct answer is option " D "

7 0
3 years ago
Read 2 more answers
The density of solid Cr is 7.15 g/cm3. How many atoms are present per cubic centimeter of Cr?
Masja [62]
To calculate the number of atoms of Cr, we first find the number of moles per unit of cubic centimeter of Cr. Then, use avogadros number for the number of atoms. Calculations are as follows:

1 cm^3 (7.15 g/cm^3) (1 mol / 51.996 g Cr) = 0.14 mol Cr

0.14 mol Cr ( 6.022 x 10^23 atoms Cr / 1 mol Cr ) = 8.28 x 10^22 atoms Cr
8 0
3 years ago
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