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devlian [24]
4 years ago
10

What inference might a scientist make if she observed an increase in her energy after eating an afternoon snack?

Physics
1 answer:
Llana [10]4 years ago
7 0
<span>The energy production in cell increased. Food gets transformed to ATP a form of chemical energy as a result of respiration taking place in cells. When food is taken it gets digested and transported to cells by the blood for respiration and energy is released. So the scientist will arrive at the inference that the rate of energy increased by having the afternoon snack.</span>
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A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 24.3 m/s . A 1.0-kg stone is thrown
defon

Answer:

-969.06

-286.74

698.7

-115.6, 12.9

-139.9, 12.9

Explanation:

Given that

Speed v, wrt y = -24.3 m/s

Speed v, wrt x = 12.9 m/s

time t, = 11.8 s

a

Using the formula

H(t) = ut - 1/2gt², where u = v wrt y

H(t) = -24.3 * 11.8 - 1/2 * 9.8 * 11.8²

H(t) = -286.74 - 682.28

H(t) = -969.06 m

b

H = ut, where u = v wrt y

H = -24.3 * 11.8

H = -286.74 m

H(1) = -969.06 - -286.74 = -682 m

c

Horizontal displacement, x = vt. Where v = v wrt x

x = 12.9 * 11.8

x = 152.22 m

d = √(H1² + x²)

d = √682² + 152²

d = 465124 + 23104

d = √488228

d = 698.7 m

d

Vertical component =

-gt - 0 =

-9.8 * 11.8 = -115.6

Horizontal component =

v wrt x - 0

12.9 - 0 = 12.9

e

Vertical component =

-gt - v wrt y =

-9.8 * 11.8 - 24.3 = -139.9

Horizontal component =

v wrt x - 0 =

12.9 - 0 = 0

8 0
3 years ago
Suppose a child drives a bumper car head on into the side rail, which exerts a force of 3900 N on the car for 0.55 s. Use the in
-Dominant- [34]

Answer:

<em>The impulse is 2145 kg-m/s</em>

<em>The final velocity is -8.34 m/s or 8.34 m/s in he opposite direction.</em>

Explanation:

Force on the rail = 3900 N

Elapsed time of impact = 0.55 s

Impulse is the product of force and the time elapsed on impact

I = Ft

I is the impulse

F is force

t is time

For this case,

Impulse = 3900 x 0.55 = <em>2145 kg-m/s</em>

If the initial velocity was 2.95 m/s

and mass of car plus driver is 190 kg

neglecting friction, the initial momentum of the car is given as

P = mv1

where P is the momentum

m is the mass of the car and driver

v1 is the initial velocity of the car

initial momentum of the car P = 2.95 x 190 = 560.5 kg-m/s

We know that impulse is equal to the change of momentum, and

change of momentum is initial momentum minus final momentum.

The final momentum = mv2

where v2 is the final momentum of the car.

The problem translates into the equation below

I = mv1 - mv2

imputing values, we have

2145 = 560.5 - 190v2

solving, we have

2145 - 560.5 = -190v2

1584.5 = -190v2

v2 = -1584.5/190 = <em>-8.34 m/s</em>

6 0
4 years ago
Which are examples of perfectly in elastic collisions
sweet [91]
Typical examples of inelastic collision are between cars, airlines, trains, etc.
For instance, when two trains collide, the kinetic energy of each train is transformed into heat, which explains why, most of the times, there is a fire after a collision. However, the momentum of the two trains that are involved in the collision remains unaffected. So, the trains collide with all their speed, maintaining their momentum, yet their kinetic energy is transformed into heat energy.
Another way to explain a train or a car collision is this: when the two trains or cars collide, they stick together while slowing down. They slow down because their kinetic energy is gradually lost. Still, they collide because they conserve their momentum.
8 0
3 years ago
Water in central Texas comes from the Edwards
kodGreya [7K]
The answer is d my homie
8 0
3 years ago
Read 2 more answers
Question 4<br> Which of the following is the unit for Work?
Mkey [24]
<h2>Unit of Work is Joule.</h2>

<h2>Thank you</h2>
5 0
3 years ago
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