To solve this problem we will make a graph that allows us to understand the components acting on the body. In this way we will have the centripetal Force and the Force by gravity generating a total component. If we take both forces and get the trigonometric ratio of the tangent we would have the angle is,
![T_x = nsinA = \frac{mv^2}{r}](https://tex.z-dn.net/?f=T_x%20%3D%20nsinA%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
![T_y = ncosA = mg](https://tex.z-dn.net/?f=T_y%20%3D%20ncosA%20%3D%20mg)
Dividing both.
![tan A = \frac{v^2}{rg}](https://tex.z-dn.net/?f=tan%20A%20%3D%20%5Cfrac%7Bv%5E2%7D%7Brg%7D)
![tan A = \frac{11.7^2}{50*9.8}](https://tex.z-dn.net/?f=tan%20A%20%3D%20%5Cfrac%7B11.7%5E2%7D%7B50%2A9.8%7D)
![A = tan^{-1} (0.279367)](https://tex.z-dn.net/?f=A%20%3D%20tan%5E%7B-1%7D%20%280.279367%29)
![A = 15.608\°](https://tex.z-dn.net/?f=A%20%3D%2015.608%5C%C2%B0)
Therefore the angle that should the curve be banked is 15.608°
Answer:2.47
Explanation:
So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!
The work done on the box by the applied force is zero.
The work done by the force of gravity is 75.95 J
The work done on the box by the normal force is 75.95 J.
<h3>The given parameters:</h3>
- Mass of the box, m = 3.1 kg
- Distance moved by the box, d = 2.5 m
- Coefficient of friction, = 0.35
- Inclination of the force, θ = 30⁰
<h3>What is work - done?</h3>
- Work is said to be done when the applied force moves an object to a certain distance
The work done on the box by the applied force is calculated as;
![W = Fd cos(\theta)\\\\W = (ma)d \times cos(\theta)](https://tex.z-dn.net/?f=W%20%3D%20Fd%20cos%28%5Ctheta%29%5C%5C%5C%5CW%20%3D%20%28ma%29d%20%5Ctimes%20cos%28%5Ctheta%29)
where;
a is the acceleration of the box
The acceleration of the box is zero since the box moved at a constant speed.
![W = (0) d \times cos(30)\\\\W = 0 \ J](https://tex.z-dn.net/?f=W%20%3D%20%280%29%20d%20%5Ctimes%20cos%2830%29%5C%5C%5C%5CW%20%3D%200%20%5C%20J)
The work done by the force of gravity is calculated as follows;
![W = mg \times d\\\\W = 3.1 \times 9.8 \times 2.5 \\\\W = 75.95 \ J](https://tex.z-dn.net/?f=W%20%3D%20mg%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%203.1%20%5Ctimes%209.8%20%5Ctimes%202.5%20%5C%5C%5C%5CW%20%3D%2075.95%20%5C%20J)
The work done on the box by the normal force is calculated as follows;
![W = (F_n) \times d\\\\W = (mg + F sin\theta) \times d\\\\W = (mg + 0) \times d\\\\W = mgd\\\\W = 3.1 \times 9.8 \times 2.5\\\\W = 75.95 \ J](https://tex.z-dn.net/?f=W%20%3D%20%28F_n%29%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%20%28mg%20%2B%20F%20sin%5Ctheta%29%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%20%28mg%20%2B%200%29%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%20mgd%5C%5C%5C%5CW%20%3D%203.1%20%5Ctimes%209.8%20%5Ctimes%202.5%5C%5C%5C%5CW%20%3D%2075.95%20%5C%20J)
Learn more about work done here: brainly.com/question/8119756
Answer:Electromagnetic Energy Example One
activity: cellphones
type of electromagnetic: radio waves
description: we all use our phones to make phone calls and to send a text!
Electromagnetic Energy Example two
activity: microwave
type of electromagnetic: microwave radiation
description: The microwave radiation is absorbed by water molecules in the food which converts to heat intern heats the food do to high levels of radiation being emitted into the food!
Explanation:
i hope this helps you sorry if it doesn't
<span>Social
i think so ,but i am not sure</span>