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harkovskaia [24]
3 years ago
6

Which of the following examples does not illustrate Newton's first law of motion?

Physics
1 answer:
Stella [2.4K]3 years ago
6 0

Answer: B

Explanation: The rocket is accelerating the the spacecraft. Accelerating  relates to Newtons Second Law of Motion.

You might be interested in
List two fossil fuels. describe in general how fossil fuels were formed.
vazorg [7]

Fossil Fuels:

Coal and Oil

How they are formed:

Coal is formed from big plants, from a long time ago. When the big plants died, they formed layers at the bottom of swamps and the dirt began to pile up and it formed Coal.

Oil is a fossil fuel that has been formed from a large amount tiny plants and animals such as algae and zooplankton.

4 0
3 years ago
If the mass of a material is 46 grams and the volume of the material is 14 cm^3, what would the density of the material be?
umka21 [38]

<u>Answer</u>

3.2857 g/cm³


<u>Explanation</u>

Density of a material is the mass of a unit volume of that material. It's SI unit is Kg/m³ but its has other units like g/cm³.

Density  = mass/volume

             = 46/14

             = 3.2857 g/cm³

3 0
3 years ago
What is the momentum of a 546,540 kg train that is travelling at 7.8 m/s​
lara [203]

p=mv so wouldn't u multiply them?

8 0
2 years ago
Why are you able to observe the Doppler effect on earth with sound waves but not with light waves?
VladimirAG [237]

Answer: When an ambulance passes with its siren blaring, you hear the pitch of the siren change: as it approaches, the siren’s pitch sounds higher than when it is moving away from you. This change is a common physical demonstration of the Doppler effect.

Explanation:

6 0
3 years ago
50 grams of ice cubes at -15°C are used to chill a water at 30°C with mass mH20 = 200 g. Assume that the water is kept in a foam
Arada [10]

Answer : The final temperature is, 25.0^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ice = 2.09J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ice = 50 g

m_2 = mass of water = 200 g

T_f = final temperature = ?

T_1 = initial temperature of ice = -15^oC

T_2 = initial temperature of water = 30^oC

Now put all the given values in the above formula, we get:

50g\times 2.09J/g^oC\times (T_f-(-15))^oC=-200g\times 4.184J/g^oC\times (T_f-30)^oC

T_f=25.0^oC

Therefore, the final temperature is, 25.0^oC

5 0
3 years ago
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