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3 years ago

Which of the following examples does not illustrate Newton's first law of motion?

Physics

1 answer:

Stella [2.4K]3 years ago

6 0

Answer: B

Explanation: The rocket is accelerating the the spacecraft. Accelerating relates to Newtons Second Law of Motion.

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A conducting loop is lying flat on the ground. The north pole of a bar magnet is grought down toward the loop. As the magnet app

IceJOKER [234]

Answer:

The current in the loop will flow in anticlockwise direction , and the magnetic field created by the induced current point up.

Explanation:

7 0

3 years ago

A neutral wire without current flowing creates A.) an electric field. B.) a magnetic field. C.) both an electric field and magne

Wewaii [24]

Believe the answer is B

6 0

3 years ago

. Calcula el módulo del vector resultante de dos vectores fuerza de 9 [N] y 12 [N] concurrentes en un punto o, cuyas direcciones

ycow [4]

Answer:

a) 20.29N

b) 19.42N

c) 15N

Explanation:

To find the magnitude of the resultant vector you can consider an axis in the middle of the vector, from which you can calculate the components of the vectors by using the angles given:

a) for 30°

$F_1=[9cos(15\°)\hat{i}+9sin(15\°)\hat{j}]N\\\\F_1=[8.69\hat{i}+2.32\hat{j}]N\\\\F_2=[12cos(15\°)\hat{i}-12sin(15\°)\hat{j}]N\\\\F_2=[11.59\hat{i}-3.10\hat{j}]N\\\\F=F_1+F_2=20.28N\hat{i}-0.78N\hat{j}\\\\|F|=\sqrt{(20.28N)^2+(0.78N)^2}=20.29N$

F = 20.29N

b) for 45°

$F_1=[9cos(22.5\°)\hat{i}+9sin(22.5\°)\hat{j}]N\\\\F_1=[8.31\hat{i}+3.44\hat{j}]N\\\\F_2=[12cos(22.5\°)\hat{i}-12sin(22.5\°)\hat{j}]N\\\\F_2=[11.08\hat{i}-4.59\hat{j}]N\\\\F=F_1+F_2=19.39N\hat{i}-1.15\hat{j}\\\\|F|=\sqrt{(19.39N)^2+(1.15N)^2}=19.42N$

F= 19.42N

c) for 90°

for this case you can consider that the direction of both vectors are the y and x axis of the Cartesian plane:

$F_1=9N\hat{i}\\\\F_2=12N\hat{j}\\\\F=\sqrt{(9N)^2+(12N)^2}=15N$

F=15N

6 0

3 years ago

Ampere second could be the unit of : O power O conductance O energy O charge

ASHA 777 [7]

Answer:

Charge

Explanation:

Unit of ampere is defined as the coulomb of charge per unit time which is in seconds.

$i=\frac{q}{t}$

Here, i is in ampere, qis the charge which is in coulomb, and the t is in sec which is time.

Therefore,

$q=it$

Charge=ampere-second.

Therefore, the unit ampere-second will represent the charge.

8 0

4 years ago

A 60 newton force is directed in a southwest direction. What are the magnitudes of the force components in the south and west di

JulijaS [17]

Hello
This question is to be tackled using vectors. When we look at the Southwest direction, we know it lies exactly between the South and West directions, producing an angle of 45 degrees. When we take sin(45) and multiply it by the original force, we obtain the component towards West; that is:
60 * sin (45) = 42.4 Newtons
And cos(45) gives us the force towards the South direction; that is:
60 * cos(45) = 42.4 Newtons
This can also be checked by using the formula of the magnitude of a vector and squaring 42.4, adding it to the square of 42.4 and then taking the square root of the answer.
sqrt(42.4^2 + 42.4^2) = sqrt(3600) = 60

5 0

3 years ago