The Richter Scale<span> is not commonly </span>used<span> anymore, except for small </span>earthquakes<span>recorded locally, for which ML and Mblg are the only </span>magnitudes<span> that can be measured. For all other </span>earthquakes<span>, the </span>moment magnitude scale<span> is a more accurate measure of the </span>earthquake<span> size.</span>
Answer: 35000 J or 35kJ
Explanation:
Use equation for kinetic energy : Ek=mV²/2
m=700 kg
V=10m/s
-------------------
Ek= 700kg*100m²7s²/2
Ek=35000 J=35kJ
Weight is mass x gravity, so you'd multiply the mass of the astronaut by the gravitational pull.
Answer:
160 m/s
Explanation:
The Ferrari is moving by uniformly accelerated motion, with constant acceleration of a = 50 m/s^2, and initial velocity u = 10 m/s. The velocity at time t of the car is given by

where
u = 10 m/s
a = 50 m/s^2
If we substitute t = 3 s into the equation, we can find the velocity of the car after 3 seconds:

Answer:
The near point of an eye with power of +2 dopters, u' = - 50 cm
Given:
Power of a contact lens, P = +2.0 diopters
Solution:
To calculate the near point, we need to find the focal length of the lens which is given by:
Power, P = 
where
f = focal length
Thus
f = 
f =
= + 0.5 m
The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.
Now, by using lens maker formula:

where
u = object distance = 25 cm = 0.25 m = near point of a normal eye
u' = image distance
Now,



Solving the above eqn, we get:
u' = - 0.5 m = - 50 cm