The answer will be 42x. Can I have brainliest if you don’t mind?
Answer:
..
Step-by-step explanation:
..
Answer:
10.9
Step-by-step explanation:
adding there squres you get 118.1 taking the squareroot of that you get 10.9
5+2=7 which means there will be 7 zeros so it is 10000000 times greater than
105 different outfits can wear on an individual day
<em><u>Solution:</u></em>
I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work
To find: Number of different outfits can I wear on an individual day
First he has to decide on a pair of pants and he has 5 different choices
For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations
For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits
In short we can say,
different outfits = 7 x 5 x 3 = 105
So there 105 different outfits can wear on an individual day
