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Natalija [7]
3 years ago
13

What is : 1.25 + (-0.75)

Mathematics
2 answers:
zhuklara [117]3 years ago
8 0

Answer:

0.5

Step-by-step explanation:

use a cauculator

wariber [46]3 years ago
5 0

Answer:

0.50

Step-by-step explanation:

You can rewrite this as 1.25 - 0.75. When you do this, you will get 0.50

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What is this? Please answer with an explanation
Pie

Answer:

5

Step-by-step explanation:

1. in order to calculate all the required values, it needed to solve:

\sqrt{x-5} \geq 0; \  \ x\geq 5.

2. x≥5 means, that x∈[5;+∞), where beginnig is '5'.

3 0
3 years ago
Which of the following are solutions to the equation below? Check all that apply. 4x2 + 4x + 1 = 9​
Vilka [71]

Answer:

4x^2 + 4x + 1=9

4x^2 + 4x - 8=0

Dividing both sides by 4

x^2 + x -2=0

It can be written as

x^2 + 2x - x - 2=0

x(x+2) -1(x+2)=0

taking (x+2) as common on LHS

Then, (x+2)(x-1)=0

Now first equate x+2=0  ie x=-2

then                 x-1=0 ie x=1

Therefore, x has two values(roots)

that is -2,1

4 0
3 years ago
PLSS helpp <br><br> btw have a nice day
Natali5045456 [20]
It’s the first one! The table shows X going up and Y going down, so the slope would be negative!
8 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
Ax^2+bx+c=(x+p)(x+q) What you know about p and q if c is less than 0. WILL MAKE BRAINLIEST!! If u provide EXPLANATION :)
Murljashka [212]

Answer:

From what I know there is no q.

p=0 I put a slight explanation below.Hope it helps

Step-by-step explanation:

Ax^2+bx+c-p=x

Ax^2+bx+c-p-x=x-x

Ax^2+(b-1)x+c-p=0

3 0
3 years ago
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