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irina [24]
3 years ago
9

In the mass spectrum of the molecule phenol, C6H5OH, the approximate intensity of the peak at m/z 95, relative to the molecular

ion at 94 will be which of the following?
a. 94%
b. 6.6%
c. 7.0%
d. 10.0%
Chemistry
1 answer:
klasskru [66]3 years ago
6 0
The correct answer to thi
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Find the final product for: Li + Br and show work.
miskamm [114]

Lithium is atomic number 3, so it has valency 1

While, Bromine is atomic number 35, and has valency 1

Lithium has an extra electron while Bromine need an electron, since they both need and have one electron, the form

LiBr (Lithium Bromide) where Li is +ve charged and Br is -ve charged

Happy to help :)

7 0
3 years ago
For a particular isomer of C8H18, the combustion reaction produces 5104.1 kJ of heat per mole of C8H18(g) consumed, under standa
Vladimir79 [104]

Answer:

Explanation:

Hello,

Considering the chemical reaction, the enthalpy of reaction is given by:

ΔH°rxn=ΔfHCO2+ΔfHH2O-ΔfHC8H18

(ΔfHO2=0)

Taking into account that the reaction produces energy, ΔH°rxn is negative. No, solving for ΔfHC8H18:

ΔfHC8H18=-ΔH°rxn+8*ΔfHCO2+9*ΔfHH2O

ΔfHC8H18=-(-5104.1 kJ/mol)+9*(-292.74kJ/mol)+8*(-393.5 kJ/mol)

ΔfHC8H18=-678.56 kJ/mol

Best regards.

3 0
3 years ago
The reduction of ketone groups, such as those present on coq, produces alcohols. in contrast, oxidation of aldehydes produces wh
nevsk [136]

On oxidation of aldehydes produces carboxylic acid functional group.

The product of oxidation of aldehydes depends upon whether the reaction occur in acidic medium or alkaline condition.

If oxidation of aldehydes occurs under acidic condition the product is carboxylic acid but if oxidation of aldehydes occurs under alkaline condition then reduce as well as oxidized product obtained which is known as disproportional product.

The  oxidation of aldehydes occur through potassium dichromate, potassium permanganate or many more. The oxidation of aldehydes in the presence of base is known as cannizzaro's reaction.

learn about oxidation

brainly.com/question/16976470

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