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IceJOKER [234]
3 years ago
5

An atom has three full orbitals in its second energy level.

Chemistry
2 answers:
ICE Princess25 [194]3 years ago
7 0
Orbitals am only hold two electrons each, so 3 orbitals can hold 6 electrons
DIA [1.3K]3 years ago
7 0

Answer:

6 hope this helps

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The less dense areas in a sound wave are called _____.
Vitek1552 [10]
The less dense areas in a sound wave is called a rarefaction or rarefactions if there are multiple.
3 0
3 years ago
Read 2 more answers
Wood has a density of 0.531 g/cm3. What is the volume of 44 grams of wood?
Sunny_sXe [5.5K]

Answer:

<h3>The answer is 82.86 cm³</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of wood = 44 g

density = 0.531 g/cm³

It's volume is

volume =  \frac{44}{0.531}  \\  = 82.86252354...

We have the final answer as

<h3>82.86 cm³</h3>

Hope this helps you

3 0
3 years ago
The mass of an atom is equal to the number of
Solnce55 [7]

Explanation:

proton number and neutron number sums up to form the mass number

5 0
3 years ago
Read 2 more answers
9. Calculate the specific heat capacity of titanium if a 43.56 g sample absorbs 0.476 kJ as its temperature changes from 20.5 oC
Shalnov [3]

Answer:

c = 0.528 J/g.°C

Explanation:

Given data:

Mass of titanium = 43.56 g

Heat absorbed = 0.476 KJ  = 476 j

Initial temperature = 20.5°C

Final temperature = 41.2°C

Specific heat capacity = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 41.2°C - 20.5°C

ΔT = 20.7 °C

476 J = 43.56 g × c × 20.7 °C

476 J = 901.692 g.°C × c

c = 476 J / 901.692 g.°C

c = 0.528 J/g.°C  

8 0
3 years ago
The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins
saul85 [17]
The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
So, we know:
t = 10 min
<span>t_{1/2} = 2.5 min

We need:
n = ?
x = ?
</span>
We could first use the second equation to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{10 min}{2.5 min}
⇒ n=4<span>
</span>
Now we can use the first equation to calculate the remained fraction of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^4
<span>⇒x= \frac{1}{16}</span>
3 0
3 years ago
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