1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vesna [10]
4 years ago
7

100 points, brainliest, and free points if you answer all correctly

Physics
2 answers:
ArbitrLikvidat [17]4 years ago
7 0

1. If the red blood cells are placed in beaker B, water would move out of the cells by osmosis and cause the cells to shrink. this is because the the solution is hyper tonic compared to the red blood cell.  

2. If some red blood cells are placed in beaker A,  

Water would move into the cells by osmosis and the cells would swell.

3. The concentration of water inside and outside the cells will be equal so no osmosis would occur. There is no osmotic pressure.

4. Water takes part in the production of lipids and carbohydrates.

5. The membrane and water are both involved in the movement of materials into and out of the cell. The membrane is semipermeable therefore it allows the transmission of materials into and out of the cell. water acts as a solvent for the materials entering the cell as in their original forms, they can not enter through the cell membrane pores.

6. The membrane and water are both involved in the movement of materials into and out of the cell. The membrane is semipermeable therefore it allows the transmission of materials into and out of the cell. water acts as a solvent for the materials entering the cell as in their original forms, they can not enter through the cell membrane pores.

7. OSMOSIS AND DIFFUSION are both examples of passive transport as the cells do not take part in the transport. It only occurs due to uncontrollable conditions that occur in a cycle in the cell.

Genrish500 [490]4 years ago
6 0

1.the third on 2. the last one 3.the first one 4.the second one 5.the first one 6.the second one 7.the third one

You might be interested in
A 17 kg box experiences an applied force of +175 N and a force of friction of -125 N. While experiencing these unbalanced forces
Flura [38]

Answer: (b)

Explanation:

Given

Mass of box m=17\ kg

Applied force F=175\ N

Friction force f=-125\ N

Box travels a distance of s=15\ m

time taken t=5.25\ s

Net unbalanced force F_{net}=175-125=50\ N

Work done by the unbalanced force

\Rightarrow W=F_{un}\cdot s\\\Rightarrow W=50\times 15\\\Rightarrow W=750\ N

Power developed by unbalanced force

\Rightarrow P=\dfrac{W}{t}\\\\\Rightarrow P=\dfrac{750}{5.25}\\\\\Rightarrow P=142.85\approx 1423\ W

Thus, option (b) is correct.

7 0
3 years ago
The position of galaxies in the universe was once hypothesized to be
vladimir1956 [14]
The best answer would be A
6 0
3 years ago
A spherical balloon is made from a material whose mass is 3.30 kg. The thickness of the material is negligible compared to the 1
stellarik [79]

Answer:

563712.04903 Pa

Explanation:

m = Mass of material = 3.3 kg

r = Radius of sphere = 1.25 m

v = Volume of balloon = \frac{4}{3}\pi r^3

M = Molar mass of helium = 4.0026\times 10^{-3}\ kg/mol

\rho = Density of surrounding air = 1.19\ kg/m^3

R = Gas constant = 8.314 J/mol K

T = Temperature = 345 K

Weight of balloon + Weight of helium = Weight of air displaced

mg+m_{He}g=\rho vg\\\Rightarrow m_{He}=\rho vg-m\\\Rightarrow m_{He}=1.19\times \frac{4}{3}\pi 1.25^3-3.3\\\Rightarrow m_{He}=6.4356\ kg

Mass of helium is 6.4356 kg

Moles of helium

n=\frac{m}{M}\\\Rightarrow n=\frac{6.4356}{4.0026\times 10^{-3}}\\\Rightarrow n=1607.85489

Ideal gas law

P=\frac{nRT}{v}\\\Rightarrow P=\frac{1607.85489\times 8.314\times 345}{\frac{4}{3}\pi 1.25^3}\\\Rightarrow P=563712.04903\ Pa

The absolute pressure of the Helium gas is 563712.04903 Pa

3 0
3 years ago
Factors that affect the light intensity received from a source
Roman55 [17]
Light intensity and distance is interrelated. When the distance changes, the intensity of light changes. This relationship is called inverse-square relationship. The inverse-square relationship refers to the fact that when distance changes, light intensity also changes: inverse because when distance decreases, light density increases and when distance increases, the latter decreases; square refers to the fact that light intensity and distance is not a one-to-one relationship.



6 0
3 years ago
The process of heat radiation is the ONLY method of heat transfer that can occur _____.
Neko [114]
B) through space I am sorry if it is wrong
7 0
3 years ago
Read 2 more answers
Other questions:
  • Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s
    5·1 answer
  • Read each scenario and then answer the question. Scenario A: A 6-kg bucket is raised a distance of 6 m. Scenario B: A 9-kg bucke
    15·2 answers
  • Which of the following atoms is considered neutral? An atom with 7 protons, 7 neutrons & 8 electrons An atom with 3 protons,
    6·1 answer
  • Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76
    12·2 answers
  • Add 1299 g and 45.1 kg and express your answer in milligrams (mg) to the correct number of significant figures. A) 4.64 x 10t mg
    8·1 answer
  • What is liquid pressure? and tell me its si unit please ​
    14·2 answers
  • A runner is traveling with an initial velocity of 0.3 m/s in the positive direction accelerates at a constant rate of 0.4m/s^2 f
    6·1 answer
  • Half Time At 3:00 the hour hand and the minute hand of a clock point in directions that are 90.0
    12·1 answer
  • A car has a mass of 1800 Kg. If the cars engine provides a net forward force of 3600 N, what is the acceleration of the car
    10·1 answer
  • A heavy crate is pushed across a floor at a constant velocity. Friction is present between the crate and floor. During this moti
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!