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liraira [26]
3 years ago
9

An object that falls and accelerates solely as a result of gravity is said to be in

Physics
1 answer:
krok68 [10]3 years ago
3 0
I think the answer is c
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Each liter of air has a mass of 1.80 grams. How many liters of air are contained in 2.5x10 to the third power kg of air?
valentinak56 [21]
Note: 2.5 * 10^3 kg = 2.5 * 10^3 * 10^3 = 2.5 * 10 ^6 g,  Because 1 kg = 10^3 g

This is simple proportion

1.80 grams of air  has a volume of 1 liter.

1 gram of air would have a volume of (1/1.8) liter

Therefore, 2.5 * 10^6 g would have:    2.5*10^6  * (1/1.8) = 1.3888 * 10^6 liters of air.
5 0
3 years ago
Three resistors, of 100, 200, and 300 ohms are connected in parallel. What is their equivalent resistance?
garri49 [273]

Answer:

Equivalent resistanfe in parallel (R):

1/R = 1/100 + 1/200 + 1/300

1/R = (6 + 3 + 2)/600

1/R = 11/600

R = 600/11 = 54.55 ohms

3 0
3 years ago
Read 2 more answers
I have three questions. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s.
AfilCa [17]

1. 5.5 m/s

We can solve the problem by applying the law of conservation of momentum. The total momentum before the collision must be equal to the total momentum after the collision, so we have:

m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where

m1 = 0.4 kg is the mass of the ball

u1 = 18 m/s is the initial velocity of the ball

m2 = 0.2 kg is the mass of the bottle

u2 = 0 is the initial velocity of the bottle (which is initially at rest)

v1 = ? is the final velocity of the ball

v2 = 25 m/s is the final velocity of the bottle

Substituting and re-arranging the equation, we can find the final velocity of the ball:

v_1 = \frac{m_1 u_1 - m_2 v_2}{m_1}=\frac{(0.4 kg)(18m/s)-(0.2 kg)(25 m/s)}{0.4 kg}=5.5 m/s


2. 22.2 m/s

We can solve the problem again by using the law of conservation of momentum; the only difference in this case is that the bullet and the block, after the collision, travel together at the same speed v. So we can write:

m_1 u_1 + m_2 u_2 = (m_1 +m_2) v

where

m1 = 0.04 kg is the mass of the bullet

u1 = 300 m/s is the initial velocity of the bullet

m2 = 0.5 kg is the mass of the block

u2 = 0 is the initial velocity of the block (which is initially at rest)

v = ? is the final velocity of the bullet+block, which stick and travel together

Substituting and re-arranging the equation, we can find the final velocity of bullet+block:

\frac{m_1 u_1}{m_1 +m_2}=\frac{(0.04 kg)(300 m/s)}{0.04 kg+0.5 kg}=22.2 m/s


3. 6560 N

The impulse exerted on the ball is equal to its change in momentum:

I=\Delta p (1)

The impulse can be rewritten as product between force and time of collision:

I=F \Delta t

while the change in momentum of the ball is equal to the product between its mass and the change in velocity:

\Delta p = m\Delta v = m(v_f -v_i)

So, eq.(1) becomes

F \Delta t = m(v_f -v_i)

where:

F = ? is the unknown force

\Delta t = 0.002 s is the duration of the impact

m = 0.16 kg is the mass of the ball

v_f = 44 m/s is the final velocity of the ball

v_i = -38 m/s is its initial velocity (we must add a negative sign, since it is in opposite direction to the final velocity)

So, by using the equation, we can find the force:

F=\frac{m (v_f -v_i)}{\Delta t}=\frac{(0.16 kg)(44 m/s-(-38 m/s))}{0.002 s}=6560 N

7 0
4 years ago
The star Betelgeuse is 6.1 x 10^18 m away from Earth. How old is the light we see from that star when it reaches us? There are 3
castortr0y [4]

Answer:

635 years old

Explanation:

The light reaching the earth from the sun will travel at a speed called the speed of light, and this has a universal value of 3 × 10⁸ m/s. Bearing this in mind, let us calculate the age of the light reaching the Earth from the sun:

Distance of star from Earth = 6.1 × 10⁸m

Speed of light = 3 × 10⁸ m/s

We have distance and speed, let us calculate the time of travel of the light from the star to the earth.

Distance = speed × time

6.1 × 10⁸ = 3 × 10⁸ × time

time = \frac{6.1 \times 10^{18}}{3 \times 10^8}

In order to do the division above, we will divide the whole numbers normally, then we will apply the law of indices to the power that says:

Xᵃ ÷ Xᵇ = X⁽ᵃ⁻ᵇ⁾

\therefore time = \frac{6.1 \times 10^{18}}{3 \times 10^8}\\= \frac{2.03 \times 10^{(18-8)}}{1} \\= 2.03 \times 10^{10}}\ seconds

Next, we are told that there are 3.2 × 10⁷ seconds in a year.

∴ The number of years travelled by the light from the star:

3.2\ \times 10^7\ seconds = 1\ year\\1\ second =  \frac{1}{3.2\ \times 10^7} \\\therefore 2.03 \times 10^{10}\ seconds = \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}

please note that:

2.03 × 10¹⁰ = 20300000000

3.2 × 10⁷ = 32000000

\therefore \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}\\= \frac{20300000000}{32000000} \\\\= \frac{20300}{32} \\= 634.347\ years\\

The closest answer in the option is 635 years, and we are short of this by some points due probably to approximations in the calculation.

8 0
3 years ago
Which scientist was the first to propose the heliocentric model of the universe? A. Aristotle B. Isaac Newton C. Galileo Galilei
Annette [7]

The answer would defiantly be option D "Nicolaus Copernicus." Copernicus was first to purpose the model of the universe, back in 1543 he presented a heliocentric model of the universe, he also made a geocentric model.

Hope this helps!

Nonportrit

6 0
4 years ago
Read 2 more answers
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