Answer:
Explanation:
Given:
- area of piston on the smaller side of hydraulic lift,
- area of piston on the larger side of hydraulic lift,
- Weight of the engine on the larger side,
Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.
is the required effort force.
Answer:
The wave velocity and the wavelength are related to the wave's frequency and period by vw=λT or vw=fλ. The time for one complete wave cycle is the period T. The number of waves per unit time is the frequency ƒ. The wave frequency and the period are inversely related to one another.
Explanation:
I will be making the assumption that you aren't actually really throwing the object over a bridge but rather dropping it as no initial velocity is actually given, which is required to do this problem. This will mean that initial velocity will be zero in this case.
First off, let's state all of the information we are given (the five kinematic quantities)
v₁ = 0 m/s
v₂ = cannot be determined
Δd = ?
Δt = 8 seconds
a (g) = 10 m/s² [down]
Now analyzing what we have, we can determine that we have 3 given quantities, 1 we must solve for, and 1 that cannot be found given our current information.
The five kinematic equations are useful because they all contain four kinematic quantities, and with different combinations too. In this case, we have three (v₁, Δt, a) and have to solve for Δd. The kinematic equation that fits with this would be:
Δd = v₁Δt + 0.5(a)(t)²
We can plug in our given values now.
Δd = 0 m/s(8 s) + 0.5(10 m/s²)(8 s)²
Δd = 0.5(10 m/s²)(8 s)²
Δd = <u>3</u>20 m
Therefore, the total displacement of the object would have to be 300m. (Due to significant digit rules)
I believe that it most likely would be C,
