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Bond [772]
3 years ago
6

How do we know how much gravitational force objects have?

Physics
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

With a force of 1 Newton, an object weighing 100 grams is dragged towards the planet's center. On Earth, an item with a mass of 100 grams has a gravitational pull of only 1%, or about kg.

Explanation:

i hope this helps

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What speed should a satellite with a mass of 1500 kg at 8,500 km above the center of the earth be traveling at in order to stay
hodyreva [135]

Answer:

6844.5 m/s.

Explanation:

To get the speed of the satellite, the centripetal force on it must be enough to change its direction. This therefore means that the centripetal force must be equal to the gravitational force.

Formula for centripetal force is;

F_c = mv²/r

Formula for gravitational force is:

F_g = GmM/r²

Thus;

mv²/r = GmM/r²

m is the mass of the satellite and M is mass of the earth.

Making v the subject, we have;

v = √(GM/r)

We are given;

G = 6.67 × 10^(-11) m/kg²

M = 5.97 × 10^(24) kg

r = 8500 km = 8500000

Thus;

v = √((6.67 × 10^(-11) × (5.97 × 10^(24)) /8500000) = 6844.5 m/s.

7 0
3 years ago
Read 2 more answers
What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo
Vitek1552 [10]

Answer:

1315789.47368 lines/m

Explanation:

m = Order = 1

sin\theta = 1 For maximum condition

\lambda = Wavelength = 760 nm maximum

From Rayleigh criteria we have the expression for the gap

d=\dfrac{m\lambda}{sin\theta}\\\Rightarrow d=\dfrac{1\times 760}{1}\\\Rightarrow d=760\ nm

The number of lines is the reciprocal of the slit distance

n=\dfrac{1}{d}\\\Rightarrow n=\dfrac{1}{760\times 10^{-9}}\\\Rightarrow n=1315789.47368\ /m

The number of lines is 1315789.47368 per meter

7 0
3 years ago
Consider two blocks of copper. Block A contains 800 atoms and initially has a total of 20 quanta of energy. Block B contains 200
marishachu [46]

Answer:

Option B and Option D are true

Explanation:

We are given;

Number of atoms in block A = 800

Energy content in block A = 20 quanta

Number of atoms in block B = 200

Energy content in block B = 80 quanta

The energy of a system which is an extensive quantity,depends on the mass or number of moles of the system. However, at equilibrium, the energy density of the two copper blocks will be equal. That is, each atom of Cu in the two blocks will, on average, have the same energy. Because block A has 4 times more atoms than block B, it will have 4 times more quanta of energy. Thus, option B is therefore true while option A is false.

Temperature is a measure of the average kinetic energy of the atoms in a material. Now, if each atom in blocks A and B have the same average energy, then the temperatures of blocks A and B will be equal at equilibrium. Thus, option D is true.

Entropy of a system is an extensive quantity that depends on the the mass or number of atoms in the system. Because block A is bigger than block B, it will have higher entropy. However, that the specific entropy (the entropy per mole or per unit mass) is an intensive quantity -- it is independent of the size of a system. The molar entropy of blocks A and B are equal at equilibrium. Thus option C is false.

8 0
3 years ago
Are photons causing the electrons to flow off of the target? ( the target is calcium)
Sliva [168]

Answer:

The energy lost by the atoms is given off as an electromagnetic wave. ... even if it's not very intense, will always cause electrons to be emitted.

Explanation:

5 0
3 years ago
1.What is the kinetic energy of an object with a velocity of 7m / s and a mass of 14kg
Vlada [557]

Answer:

Explanation:

The formula for KE is

KE=\frac{1}{2}mv^2 and we fill in to solve for KE:

KE=\frac{1}{2}(14)(7.0)^2 I used 2 significant digits in the velocity because 1 isn't accurate enough. Therefore, my answer will be rounded to 2 sig fig's:

KE = 340 J (rounded from 343). And we do the exact same thing in #2:

KE=\frac{1}{2}(5.0)(5.0)^2 (Used 2sig fig's for both the mass and the velocity) to get

KE = 63 J (rounded from 62.5)

3 0
3 years ago
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