Answer:
2.5 m
Step-by-step explanation:
The perimeter of any geometric shape is calculated by adding all side lengths together
if we call the missing side x
The perimeter : x + 4 + 5 + 3.5 = 15 ➡ x + 12.5 = 15 and x = 15 - 12.5 ➡ x = 2.5
Answer:

Step-by-step explanation:
You're multiplying two factors together (because at the start, it says the product of)
The first factor is the quotient of A, and the sum of B and C, so A divided by (B + C)
The second factor is whatever the product of D and E is, so you have to multiply those together first
53.3
Step-by-step explanation:
Make an equation.
40y = 3x
zy=4x
Substitute y
What are the options it gives you?
Answer:
(1)14.9% (2) 2.96% (3) 97.04%
Step-by-step explanation:
Formula for Poisson distribution:
where k is a number of guests coming in at a particular hour period.
(1) We can substitute k = 7 and
into the formula:


(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours




(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore: