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Katyanochek1 [597]
2 years ago
5

In an equilibrium reaction with a Keq of 1×10^8,the-

Chemistry
1 answer:
BabaBlast [244]2 years ago
5 0
It is not exothermic because it would be negative. Since energy is required it is not spontaneous. Since heat is a reactant since the equation is endothermic since the Keq is positive, the reactants would be favored. (A)
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Summarize: Complete the following statements:
egoroff_w [7]

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Explanation:

Taking into account the definition of Avogadro's Number, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

1 mole of any compound contains 6.023×10²³ molecules

You have to know that Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole.

Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression.

Avogadro's number applies to any substance, because the number of elementary units in a mole of a substance is, by definition, a  constant that does not depend on the material or the type of particle considered.

So, in this case, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

1 mole of any compound contains 6.023×10²³ molecules

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4 0
2 years ago
How is a molecule of hydrogen formed from two hydrogen atoms?
Shtirlitz [24]
A molecule of hydrogen is formed by two hydrogen atoms, that is a fact.

How does it work? When two atoms, known as "diatomic" pair with another in a bond known non-polar covalent bonds. Where they equally share electrons. A Hydrogen atoms needs 1 more electrons to fill its first shell fully and have a full valence shell. So if two H's share their electrons, they'll both have a full V-Shell!

That's the basics of both the H-H bond and all the other diatomic bonds as well. 
8 0
3 years ago
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