Complete Question
The complete question is shown on the first uploaded image
Answer:
The initial concentration is 
Explanation:
From the question we are told that
The volume of solution A is 
The concentration of A is 
The volume of solution B is 
The volume of water is 
Generally the law of dilution is mathematically represented as
Where 
is the concentration of the mixture
is the volume of the mixture which is mathematically evaluated as
So
substituting values
Note the mixture obtained is 
Answer:
Explanation:
honesty i just know it has to be b or d because bases don’t donate. acids donate.
Answer:
20.54 g of H₂O
Explanation:
Since you already have a balanced equation, the next step is to see the ratio between the ammonium nitrate and water in the equation:
NH4NO3(s)—N2O(g)+2H2O
1 mole of ammonium nitrate produces 2 moles of H2O
So we have the ration:
Let's leave that for later use.
Next step is to covert the mass given into moles. We do that by getting the molar mass of the given and using that as a conversion factor:
Element number of molar mass
atoms of each element
N = 2 x 14.01 g/mole = 28.02 g/mole
H = 4 x 1.01 g/mole = 4.01 g/mole
O = 3 x 16.00 g/mole = <u>48.00 g/mole </u>
80 .03 g/mole
Now we can convert:
Now we can use this to determine how many moles of H2O this would produce by using the ration we solved for earlier.
And we convert that by getting the molecular mass of H2O, which is 18.02 g/mole:
But this is only if the whole 45.7 g of ammonium nitrate is used up.
